Answer:
7/6π, 1/6π
Step-by-step explanation:
We know that tan is sine/cosine, so cot is cosine/sine.
In this case, we know cotθ = √3
As the number is positive, using the unit circle, we now can say that the two solutions are in quadrants I and III.
Taking a look at the unit circle, we can finalize our answer.
Answer:
Julian has <em>16 dimes</em> and <em>6 quarters</em>
Step-by-step explanation:
Let's suppose Julian has q quarters and d dimes
The total coins are 22, that is
q+d=22
q=22-d [1]
The total amount of money he has is 310 cents which are made of 10d dimes and 25q quarters
10d+25q=310
Simplifying by 5
2d+5q=62
Using the relation [1]
2d+5(22-d)=62
2d+110-5d=62
3d=48 => d=16
q=22-16 = 6
So Julian has 16 dimes and 6 quarters
Step-by-step explanation:
1 min = 60 sec
Boxes both can fold per min = 30 + 20 = 50
No of boxes to fold = 200
Time taken in sec = 200 ÷ 50 = 4 min = 60 x 4 = 240 sec
Answer:
1. LM < PN
2. AD < DC
3. m<CAB < m<CBA
4. m<1 = m<2
Step-by-step explanation:
Recall: an angle measure is relative to the length of the opposite side. That is, the longer the side opposite to an angle, the larger the measure of that angle and vice versa.
1. LM is opposite to <LNM,
PN is opposite to <NLP
m<LNM is less than m<NLP, therefore,
LM < PN
2. AD is opposite to <ABD
DC is opposite to <DBC
m<ABD is less than m<DBC, therefore,
AD < DC
3. m<CAB is opposite to CB
m<CBA is opposite to CA
CB is less than CA, therefore,
m<CAB < m<CBA
4. The side opposite to <1 is congruent to the side opposite to <2.
Therefore,
m<1 = m<2
Answer: 
Step-by-step explanation:
The complete exercise is: "The circumference of a circle is 47.1 and the diameter of the circle is 15. Which best represents the value of π? "
In order to solve this exercise, it is important to remember that the circle can be calculated with the following formulas:
1. 
Where "C" is the circumference of the circle and "D" is the diameter of the circle.
2. 
Where "C" is the circumference of the circle and "r" is the radius of the circle (Remeber that the diameter is twice the radius).
In this case, the exercise gives you the circumference of the circle and its diameter. These are:
Then, knowing those values, you can substitute them s into the first equation , as following:
The final step is to solve for 
:
