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3 years ago

According to vsepr theory the molecular geometry for ch3+ is

Chemistry

2 answers:

CaHeK987 [17]3 years ago

8 0

According the VSEPR theory the molecular geometry for CH3+ is triagonal planar

diamong [38]3 years ago

5 0

Answer: The molecular geometry for $CH_3^+$ is trigonal planar.

Explanation

Formula used for calculating molecular weight:

$\text{Number of electrons}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom = 4

N = number of monovalent atoms bonded to central atom = 3

C = charge of cation = +1

A = charge of anion = 0

Now we have to determine the hybridization of the $CH_3^+$ molecules.

$\text{Number of electrons}=\frac{1}{2}\times [4+3-1]=3$

Bond pair electrons = 3

Lone pair electrons = 0

The number of electrons are 6 that means the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar.

As there are no lone pair of electrons, the molecular geometry also will be trigonal planar.

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For which one of the following molecules is the indicated type of hybridization not appropriate for

Aleksandr [31]

A. BeCl2 sp2

Also when you get the chance, could you mark me brainliest?

7 0

3 years ago

At 350°c, keq = 1.67 × 10-2 for the reversible reaction 2hi (g) ⇌ h2 (g) + i2 (g). what is the concentration of hi at equilibriu

mariarad [96]

According to the reversible reaction equation:

2Hi(g) ↔ H2(g) + i2(g)

and when Keq is the concentration of the products / the concentration of the reactants.

Keq = [H2][i2]/[Hi]^2

when we have Keq = 1.67 x 10^-2

[H2] = 2.44 x 10^-3

[i2] = 7.18 x 10^-5

so, by substitution:

1.67 x 10^-2 = (2.44 x 10^-3)*(7.18x10^-5)/[Hi]^2

∴[Hi] = 0.0033 M

7 0

3 years ago

Phase changes occur because_____

timama [110]

B and c is the answer

4 0

3 years ago

A magnesium ion, Mg2+, is formed from a magnesium atom, Mg.

konstantin123 [22]

Answer:

The correct row is B.

Explanation:

The formation of the magnesium ion, Mg²⁺, comes from the removal of 2 electrons from the valence shell of the magnesium atom.<em> </em>Since the remotion is of electrons, the nucleus of the atom remains the same, so the number of protons and the number of neutrons does not change.<em> </em>

If the number of proton change, then the atom also change, since the identity of an atom is related to the atomic number which is the same to the proton number.

Now, if the number of neutrons changes, then we would be in the presence of an isotope of the magnesium atom.

Therefore, the correct row is B.

I hope it helps you!

5 0

2 years ago

1. A given mass of air has a volume of 6.00 L at 80.0°C. At constant pressure, the temperature is

earnstyle [38]

3 L will be the final volume for the gas as per Charle's law.

Answer:

Explanation:

The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.

V∝ T

Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be

$\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }$

So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.

$\frac{6}{80}=\frac{V_{2} }{40}$

$V_{2}=\frac{6*40}{80}=3 L$

So, 3 L will be the final volume for the gas as per Charle's law.

4 0

3 years ago