Question

According to vsepr theory the molecular geometry for ch3+ is

Answer 1

According the VSEPR theory the molecular geometry for CH3+ is triagonal planar

Answer 2

Answer: The molecular geometry for $CH_3^+$  is trigonal planar.

Explanation

Formula used for calculating molecular weight:

$\text{Number of electrons}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom  = 4

N = number of monovalent atoms bonded to central atom = 3

C = charge of cation  = +1

A = charge of anion  = 0

Now we have to determine the hybridization of the $CH_3^+$  molecules.

$\text{Number of electrons}=\frac{1}{2}\times [4+3-1]=3$

Bond pair electrons = 3

Lone pair electrons = 0

The number of electrons are 6 that means the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar.

As there are no lone pair of electrons,  the molecular geometry also will be trigonal planar.