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A shell is fired with a horizontal velocity in the positive x direction from the top of an 80 m high cliff. The shell strikes th

Sonbull [250]

Answer:

V = 331.59m/s

Explanation:

First we need to calculate the time taken for the shell fire to hit the ground using the equation of motion.

S = ut + 1/2at²

Given height of the cliff S = 80m

initial velocity u = 0m/s²

a = g = 9.81m/s²

Substitute

80 = 0+1/2(9.81)t²

80 = 4.905t²

t² = 80/4.905

t² = 16.31

t = √16.31

t = 4.04s

Next is to get the vertical velocity

Vy = u + gt

Vy = 0+(9.81)(4.04)

Vy = 39.6324

Also calculate the horizontal velocity

Vx = 1330/4.04

Vx = 329.21m/s

Find the magnitude of the velocity to calculate speed of the shell as it hits the ground.

V² = Vx²+Vy²

V² = 329.21²+39.63²

V² = 108,379.2241+1,570.5369

V² = 109,949.761

V = √ 109,949.761

V = 331.59m/s

Hence the speed of the shell as it hits the ground is 331.59m/s

7 0

2 years ago

Two particles of equal mass m are at the vertices of the base of an equilateral triangle. The triangle’s center of mass is midwa

Helga [31]

Answer:Twice of given mass

Explanation:

Given

Two Particles of Equal mass placed at the base of an equilateral Triangle

let mass of two equal masses be m and third mass be m'

Taking one of the masses at origin

Therefore co-ordinates of first mass be (0,0)

Co-ordinates of other equal mass is (a,0)

if a is the length of triangle

co-ordinates of final mass $(\frac{a}{2},\frac{\sqrt{3}a}{2})$

Given its center of mass is at midway between base and third vertex therefore

$x_{cm},y_{cm}=\frac{a}{2},\frac{\sqrt{3}a}{4}$

$y_{cm}=\frac{m_1y_1+m_2y_2+m_3y_3}{m_1+m_2+m_3}$

$\frac{\sqrt{3}a}{4}=\frac{m\cdot 0+m\cdot 0+m'\cdot \frac{\sqrt{3}a}{2}}{m+m+m'}$

$2m+m'=4\times (\frac{m'}{2})$

$2m+m'=2m'$

$m'=2m$

8 0

2 years ago

Why do clastic sedimentary rocks generally form underwater?

alekssr [168]

Because they eventually erode and then break and end up forming underwater.

6 0

2 years ago

A school bus's velocity decreases from 15 m/s to 5 m/s forwards over a period of 10 s. What is the bus's average acceleration? [

aniked [119]

Answer:-1 m/s/s

Explanation:

4 0

2 years ago

A 5.60 kg box is at rest on a ramp set up on a truck. The ramp makes an angle of 23.0o with the horizontal. Find the following:

MakcuM [25]

Answer:An infrared sensor system is set up so that two sensors start timing when the infrared ... Determine the average acceleration during each time interval. c. ... the ground with a an initial velocity of 169 m/s at an angle of 23.0 O above the horizontal; a. ... A 4.00 kg mass is sitting at rest on a horizontal surface.

Explanation:

8 0

2 years ago