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ivann1987 [24]
3 years ago
5

A pendulum is hanging from a tower. The pendulum almost touches the ground and has a period of 18.0 s. What is the height of the

tower?
Physics
1 answer:
nadya68 [22]3 years ago
5 0
We apply the following equation

T = 2π * sqrt (L/g)

Where g is the gravity = 9.8 m/s^2

L is the longitude of the pendulum (Height of the tower)

T is the period. (T = 18s)

We find L.............> (T /2π)^2 = L/g

L = g*(T /2π)^2...........> L = 80.428 meters
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Answer:

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Explanation:

Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:

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We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges(q_1,q_2) and inversely proportional to the square of the distance(d) that separates them.

Replacing the given values, where k is the Coulomb constant:

F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N

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A child whose weight is 235 N slides down a 4.90 m playground slide that makes an angle of 37.0° with the horizontal. The coeffi
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Answer:

Explanation:

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Solving for Ff:

Ff = 0.051 * 235cos37 = 9.57 N

Now, to get the energy transferred to thermal energy (or heat) we need to get the Work done, so:

Wf = Ff * d

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As you can imagine, the gravity also does work, so:

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The formula for kinetic energy is:

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