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2 years ago

What should the operator of a stand-on vessel do when encountering a give-way vessel?.

Engineering

1 answer:

Rashid [163]2 years ago

3 0

Answer:

Stand-On Vessel - If you are the Stand-On vessel, it is your responsibility to acknowledge the intended actions of the give-way vessel. You must also maintain your current course and speed until the give-way vessel passes, or you enter a dangerous situation.

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A railcar with an overall mass of 78,000 kg traveling with a speed vi is approaching a barrier equipped with a bumper consisting

sergij07 [2.7K]

Answer:

v₀ = 2,562 m / s = 9.2 km/h

Explanation:

To solve this problem let's use Newton's second law

F = m a = m dv / dt = m dv / dx dx / dt = m dv / dx v

F dx = m v dv

We replace and integrate

-β ∫ x³ dx = m ∫ v dv

β x⁴/ 4 = m v² / 2

We evaluate between the lower (initial) integration limits v = v₀, x = 0 and upper limit v = 0 x = x_max

-β (0- x_max⁴) / 4 = ½ m (v₀²2 - 0)

x_max⁴ = 2 m /β v₀²

Let's look for the speed that the train can have for maximum compression

x_max = 20 cm = 0.20 m

v₀ =√(β/2m) x_max²

Let's calculate

v₀ = √(640 106/2 7.8 104) 0.20²

v₀ = 64.05 0.04

v₀ = 2,562 m / s

v₀ = 2,562 m / s (1lm / 1000m) (3600s / 1h)

v₀ = 9.2 km / h

5 0

3 years ago

15. A cold-chamber die-casting machine operates automatically, supported by two industrial robots.The machine produces two zinc

Softa [21]

Answer:

a. 121 Btu/lb

b. 211.8lb

c. 2.69/pc

Explanation:

See the attachments please

4 0

3 years ago

Read 2 more answers

An incoming signal is at a frequency of 500kHz. This signal needs to be acquired and all other signals attenuated. Design a pass

Finger [1]

Answer:

C_h = 0.166 nF

C_L = 0.153 nF

Explanation:

Given:

- Ideal frequency f_o = 500 KHz

- Bandwidth of frequency BW = 40 KHz

- The resistance identical to both low and high pass filter = 2 Kohms

Find:

Design a passive band-pass filter to do this by cascading a low and high pass filter.

Solution:

- First determine the cut-off frequencies f_c for each filter:

f_c,L for High pass filter:

f_c,L = f_o - BW/2 = 500 - 40/2

f_c,L = 480 KHz

f_c,h for Low pass filter:

f_c,h = f_o + BW/2 = 500 + 40/2

f_c,h = 520 KHz

- Now use the design formula for R-C circuit for each filter:

General design formula:

f_c = 1 /2*pi*R*C_i

C,h for High pass filter:

C_h = 1 /2*pi*R*f_c,L

C_h = 1 /2*pi*2000*480,000

C_h = 0.166 nF

C,L for Low pass filter:

C_L = 1 /2*pi*R*f_c,h

C_L = 1 /2*pi*2000*520,000

C_L = 0.153 nF

7 0

3 years ago

9 b. A sign (including the post and base) weighs 40 pounds and is

tigry1 [53]

Answer:

The weight should be added to the base of the sign to keep it from tipping is 65.6 lb

Explanation:

Given data:

A sigh weighs 40 pounds

Suported by an 18 in x 18 in square

Force of the wind 13.2 lb

Questions: Will the sign tip over, if yes, how much evelnly distributed weight should be added to the base of the sign to keep it from tipping, W = ?

The sign and the post have a length of 6 ft. You need to calculate the distance from the edge to the middle point:

18/2 = 9 in = 0.75 ft

Force acting in the base (40 lb):

$F=\frac{40*0.75}{6} =5lb$

The weight should be added to the base:

$(40+W)*\frac{0.75}{6} =13.2\\W=65.6lb$

8 0

4 years ago

Describe the "Bauschinger Effect" on the stress strain behaviour of steel

Rom4ik [11]

Answer:

The Bauschinger effect is the directionally determined change in the elasticity limit of a metal or alloy after primary plastic deformation. If you first deform a metal in one direction so that it is plastically deformed and then deform it in the opposite direction, the elastic limit in the opposite direction is lower.

From the point of view of the dislocation mechanism of plastic deformation, the Bauschinger effect indicates that during repeated deformation, it is easier for dislocations blocked in front of obstacles to move in the direction opposite to their movement during preliminary plastic deformation.

7 0

4 years ago