Which of the following is a advantage of a chain and sprocket over a pulley and belt system?
1 answer:
You might be interested in
Answer:
Mass of oil will be 7.176 pound
Explanation:
We have given specific gravity of oil = 0.86
We know that specific gravity is given by
Density of oil =
We have given volume of oil = 1 gallon
We know that 1 gallon = 0.003785
So mass of oil = volume ×density
mass = 0.003785×860 = 3.2551 kg
We know that 1 kg = 2.2046 pound
So 3.2551 kg = 3.2551×2.2046 = 7.176 pound
Answer:
Change in kinetic energy: 13479.77 J
Percentage change in kinetic energy = 99.85%
Explanation:
Change in momentum when the projectile becomes embedded in the block will be 0.
This means:
here subscript P means projectile, and subscript B means block.
Solving this equation we get:
(0.075 * 600) + (50 * 0) = (0.075 + 50) * V
Using this velocity we can compute the change in kinetic energy:
Initial kinetic energy = 0.5 * m * v^2
Initial kinetic energy = 0.5 * 0.075 * 600^2
Initial kinetic energy = 13500 J
Final Kinetic energy = 0.5 * m * v^2
Mass (m) = mass of block + mass of projectile = 50.075 kg
Final velocity v = 0.899 m/s
Final Kinetic Energy = 0.5 * 50.075 * 0.899^2
Final Kinetic Energy = 20.235 J
Change in kinetic energy = 13500 - 20.235 = 13479.77 J
Percentage change of kinetic energy = (13479.77 / 13500) * 100
Percentage change of kinetic energy = 99.85 %
Answer:
1st value = 1.828 * 10 ^9 gm/m^2 ------- 10th value = 7.312 * 10^9 gm/m^2
Explanation:
initial load ( Wp) = 200 g
W1 ( value by which load values increase ) = 100 g
Ten different beam loading values :
Wp + w1 = 300g ----- p1
Wp + 2W1 = 400g ---- p2
Wp + 3W1 = 500g ----- p3 ----------------- Wp + 10W1 = 1200g ---- p10
x = 10.25" = 0.26 m
b = 1.0" = 0.0254 m
t = 0.125" = 3.175 * 10^-3 m
using the following value to determine the load values at different beam loading values
attached below is the remaining part fo the solution
