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jok3333 [9.3K]
3 years ago
6

A 200-N force acts on a 10-kg object. The acceleration of the object is

Physics
1 answer:
jeyben [28]3 years ago
3 0
200N/10kg = 20 m/s^2
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The wing of an airplane experiences the forces as depicted in the vector diagram to the right. Using both one and two dimensiona
Vedmedyk [2.9K]

Answer:

A.) 3605.6 N

B.) 33.7 degree

Explanation:

To find the result force acting on the wing of the airplane, we need to resolve the forces into x and y components

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Resolving into y component:

Sum of forces = 2000N

Resultant force Fr = sqrt ( Fx^2 + Fy^2)

Fr = sqrt ( 3000^2 + 2000^2 )

Fr = sqrt ( 9000000 + 4000000 )

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Fr = 3605.6 N

Therefore, resultant force acting on the wing is 3605.6 N

The direction of the vector will be:

Tan Ø = Fy / Fx

Substitute Fx and Fy into the formula

Tan Ø = 2000 / 3000

Tan Ø = 0.66666

Ø = tan^-1(0. 66666)

Ø = 33.7 degree.

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