Clouds form when water vapor out of the air

Chemistry

1 answer:

Leto [7]2 years ago

3 0

Answer:

In the water cycle

Explanation:

Water cycle

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A gas mixture contains twice as many moles of o2 as n2. addition of 0.200 mol of argon to this mixture increases the pressure fr

pantera1 [17]

Number of moles of oxygen = x

number of moles of nitrogen = y

x = 2y

initial pressure, p1 = 0.8 atm

final pressure, p2 = 1.10 atm

At constant volume and temperature p1 / n1 = p2 / n2

=> p1 / p2 = n1 / n2

n1 = x + y = 2y + y = 3y

n2 = 0.2 + 3y

=> p1 / p2 = 3y / (0.2 + 3y)

=> 0.8 / 1.10 = 3y / (0.2 + 3y)

=> 0.8 (0.2 + 3y) = 1.10 (3y)

0.16 + 2.4y = 3.3y

=> 3.3y - 2.4y = 0.16

=> 0.9y = 0.16

=> y = 0.16 / 0.9

=. x = 2*0.16/0.9 = 0.356

Answer: 0.356 moles O2

8 0

3 years ago

HELP

Vesnalui [34]

Answer:

145.8g

Explanation:

Given parameters:

Number of moles of magnesium hydroxide = 2.5mol

Unknown:

Mass of Mg(OH)₂ = ?

Solution:

To solve this problem we use the expression below;

Mass of Mg(OH)₂ = number of moles x molar mass

Molar mass of Mg(OH)₂ = 24.3 + 2(16 + 1) = 58.3g/mol

Mass of Mg(OH)₂ = 2.5 x 58.3 = 145.8g

3 0

3 years ago

Which molecule below has hydrogen bonding? Which molecule below has hydrogen bonding? H2 CH3CH2OH HCl CH4 all of the above

QveST [7]

Answer:

$CH_3CH_2OH$

Explanation:

Hydrogen bonding:-

Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.

Partially positive end of the hydrogen atom is attracted to partially negative end of these atoms which is present in another molecule. It is strong force of attraction between the molecules.

Thus, hydrogen must be linked to electronegative atom which is oxygen, fluorine and nitrogen which is in $CH_3CH_2OH$ and thus, it will shown hydrogen bonding.

3 0

3 years ago

What is the empirical formula of a compound that is made of 3.80g of phosphorus and 0.371g of hydrogen?

lys-0071 [83]

You start by diving each quantity given by the atomic wight of each element:

Phosphorus (P) $\frac{3.8}{31} =0.123$