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spin [16.1K]
3 years ago
14

Compare the gravitational force on a 4 kg

Physics
1 answer:
Eddi Din [679]3 years ago
6 0

Answer:

  • The gravitational force by the Earth on the object, and by the object on the Earth is

  • F = GMm/R²

  • = 6.674×10−11 m3⋅kg−1⋅s−2 × 6 × 10^24 kg × 44.5 kg/(6.4 × 10^6 m)²

  • = 435 N

<u>Please note that the ration between the gravitation force 435 and the mass 44.5</u>

  • should be gravitational acceleration

  • 435/44.5 = 9.78

  • I attribute the discrepancy between 9.78 and the usual 9.81 to rounding off in the

  • Earth's weight and radius.

The mass of the Moon is M / 81.3.

The radius of the Moon is R × 0.27.

The gravitational force on the moon would be

G(M/81.3)m/(R×0.27)² = 0.17×GMm/R²

The gravitational force on the moon is smaller by the factor of about 0.17.

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Tonks changes her hair color for a party with a red color rinse. The next day, she washes the color out of her hair and it retur
Sergeu [11.5K]

Answer: No , a chemical change has not occured as it was easily reversed.

Explanation:

Chemical change is defined as a change in which rearrangement of atoms take place and leads to formation of new substances. It can only be reversed with the help of a chemical reaction.

Physical change is defined as a change which leads to change in shape, size or state of the substance changes. No new substance is formed.It can be easily reversed.

As the hair colour was washed out and returned to its original brown colour, it was a physical change.

5 0
3 years ago
A 68 kg runner exerts a force of 59N. What is the acceleration of the runner?
Korvikt [17]

Explanation:

<em><u>Newton's First Law ,</u></em>

F = ma

a = m/F

a = 68 / 59

a = 1.15 m/s2

4 0
3 years ago
Q: A: Sarah and Maria made a telephone using two cans and a string. It was a very long string. Maria went upstairs in her house
GrogVix [38]
This contraption is a lot of fun, and you really should try it
some time.

The sound waves move from one can to the other one 
by traveling through the string.
3 0
4 years ago
Read 2 more answers
Monochromatic light falls on a slit that is 2.30×10−3mm wide. Part A If the angle between the first dark fringes on either side
slava [35]

Answer:

Wavelength, \lambda=1.28\times 10^{-6}\ m

Explanation:

Given that,

Width of the slit, d=2.3\times 10^{-3}\ mm=2.3\times 10^{-6}\ m

The angle between the first dark fringes on either side of the central maximum is 34 degrees

To find,

The wavelength of the light used.

Solution,

The equation of maxima is given by :

dsin\theta=n\lambda

n = 1 here

\lambda=\dfrac{d\ sin\theta}{n}

\lambda={d\ sin\theta}

\lambda={2.3\times 10^{-6}\times sin(34)}

\lambda=1.28\times 10^{-6}\ m

So, the wavelength of the light used is 1.28\times 10^{-6}\ m. Hence, this is the required solution.

5 0
3 years ago
A bird of mass 1.5 kg is flying at 8 m/s at a height of 50 m above the ground. What is its
Bas_tet [7]

Answer:

hyalugel puchi puchi puchi tu hello hello hello hello hello hello hello hello hello hello

Explanation:

hello hello hello hello hello hello hello hello hello hello hello hello hello hello hello

6 0
3 years ago
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