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3 years ago

Compare the gravitational force on a 4 kg

Physics

1 answer:

Eddi Din [679]3 years ago

6 0

Answer:

The gravitational force by the Earth on the object, and by the object on the Earth is

F = GMm/R²

= 6.674×10−11 m3⋅kg−1⋅s−2 × 6 × 10^24 kg × 44.5 kg/(6.4 × 10^6 m)²

= 435 N

<u>Please note that the ration between the gravitation force 435 and the mass 44.5</u>

should be gravitational acceleration

435/44.5 = 9.78

I attribute the discrepancy between 9.78 and the usual 9.81 to rounding off in the

Earth's weight and radius.

The mass of the Moon is M / 81.3.

The radius of the Moon is R × 0.27.

The gravitational force on the moon would be

G(M/81.3)m/(R×0.27)² = 0.17×GMm/R²

The gravitational force on the moon is smaller by the factor of about 0.17.

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Compare and contrast microscopic and macroscopic energy transfer Give least three comparisons for each

Eduardwww [97]

Answer:

Differences

microscopic refers to substances visible to the naked eye

macroscopic are substances invisible to naked eye

Similarities

both refer to different scales that are useful to determining the size to different compounds.

Explanation:

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3 0

3 years ago

The driver of a 1000 kg car traveling at a speed of 16.7 m/s applies the brakes. If the brakes provide a force of - 8000 N to st

RSB [31]

Answer:

Given:

m=1000kg

u= 16.7m/s

v=0m/s

F=8000N

Required:

s=?

Solution:

F=m × a

8000N=1000kg × a

a=8m/s^2

Since it decelerate a= -8m/s^2

v^2 = u^2 + 2as

s=v^2 - u^2 / 2a

s= 0 - (16.7m/s)^2 / 2 × -8m/s^2

s= -278.89/-16

s= 17.43m

The car travels approximately 17.43m before it stops

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6 0

2 years ago

A conducting loop has an area of 0.065 m2 and is positioned such that a uniform magnetic field is perpendicular to the plane of

aev [14]

Answer:

initial magnetic field 1.306 T

Explanation:

We have given area of the conducting loop $A=0.065m^2$

Emf induced = 1.2 volt

Initial magnetic field B = 0.3 T

Time dt = 0.087 sec

We know that induced emf is given by $e=\frac{d\Phi }{dt}=-A\frac{db}{dt}$

$1.2=0.065\times \frac{db}{0.087}$

$db=1.606T$

So initial magnetic field = 1.606-0.3= 1.306 T

5 0

3 years ago

How many million Christmas trees were sold in the year 2000?

Sergio039 [100]

Explanation:

Christmas tree production occurs worldwide on Christmas tree farms, in artificial tree factories and from native strands of pine and fir trees. Christmas trees, pine and fir trees purposely grown for use as a Christmas tree, are grown on plantations in many western nations, including Australia, the United Kingdom and the United States. In Australia, the industry is relatively new, and nations such as the United States, Germany and Canada are among world leaders in annual production.

Great Britain consumes about 8 million trees annually, while in the United States between 35 and 40 million trees are sold during the Christmas season. Artificial Christmas trees are mostly produced in the Pearl River delta area of China. Christmas tree prices were described using a Hotelling-Faustmann model in 2001, the study showed that Christmas tree prices declined with age and demonstrated why more farmers do not price their trees by the foot. In 1993, economists made the first known demand elasticity estimates for the natural Christmas tree market.

5 0

3 years ago

A 512Hz tuning fork is used with a resonating column to determine the velocity of sound in water. If the spacing between resonan

EastWind [94]

Answer:

v= 1495.04 m/s

Explanation:

The formula for velocity of sound is given by ;

v= fλ --------where

v= velocity of sound

f= frequency of turning fork

λ = wavelength

However,

Δ L = 1/2 λ ------where Δ L is spacing between resonances.

1.46 = 1/2 λ

1.46 * 2 = λ

2.92 m = λ

v= fλ

v= 512 * 2.92

v= 1495.04 m/s

6 0

3 years ago