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spin [16.1K]
3 years ago
14

Compare the gravitational force on a 4 kg

Physics
1 answer:
Eddi Din [679]3 years ago
6 0

Answer:

  • The gravitational force by the Earth on the object, and by the object on the Earth is

  • F = GMm/R²

  • = 6.674×10−11 m3⋅kg−1⋅s−2 × 6 × 10^24 kg × 44.5 kg/(6.4 × 10^6 m)²

  • = 435 N

<u>Please note that the ration between the gravitation force 435 and the mass 44.5</u>

  • should be gravitational acceleration

  • 435/44.5 = 9.78

  • I attribute the discrepancy between 9.78 and the usual 9.81 to rounding off in the

  • Earth's weight and radius.

The mass of the Moon is M / 81.3.

The radius of the Moon is R × 0.27.

The gravitational force on the moon would be

G(M/81.3)m/(R×0.27)² = 0.17×GMm/R²

The gravitational force on the moon is smaller by the factor of about 0.17.

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Solnce55 [7]

Answer:

after 6 second it will stop

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Explanation:

given data

speed = 12 m/s

distance = 100 m

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to find out

how long does it take to stop and how far does he travel

solution

we will apply here first equation of motion that is

v = u + at   ......1

here u is speed 12 and v is 0 because we stop finally

put here all value in equation 1

0 = 12 + (-2) t

t = 6 s

so after 6 second it will stop

and

for distance we apply equation of motion

v²-u² = 2×a×s  ..........2

here v is 0 u is 12 and a is -2 and find distance s

put all value in equation 2

0-12² = 2×(-2)×s

s = 36 m

so  he travel 36 m to stop

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