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Misha Larkins [42]
3 years ago
13

What's the definition energy?​

Physics
1 answer:
Anit [1.1K]3 years ago
4 0
Energy is the quantitative property that must be transferred to an object in order to perform work on, or to heat, the object.
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Find the wavelength of radio waves of frequency 200kHz
Gala2k [10]
\lambda = \frac{c}{f}
λ - wavelength, c - the speed of light, f - frequency

f=200 \ kHz= 200 000 \ Hz \\ \\
\lambda=\frac{300 000 \ [\frac{km}{s}]}{200 000 \ [Hz]}=\frac{3}{2}=1.5 \ [km]

The wavelength of these waves is 1.5 km.
3 0
3 years ago
Read 2 more answers
A projectile is fired at time t= 0.0 s from point 0 at the edge of a cliff, with initial velocity components of Vox = 30 m/s and
BARSIC [14]

Answer:

At t = 15.0 s the magnitude of the velocity is 58.31 m/s

Explanation:

The given parameters are;

V₀ₓ = 30 m/s

V_{0y} = 100 m/s

The time of flight of the projectile = 25 s

For projectile motion;

Vₓ = V₀ × cos(θ₀)

The magnitude of the velocity V = √(V₀ₓ² + V_{0y}²)

We have the magnitude of the initial velocity = √(30² + 100²) = 10·√109 m/s

cos(θ₀) = V₀ₓ/V₀ = 30/(10·√109) = 3/√109

θ₀ = cos⁻¹(3/√109) = 73.3°

The components of the velocity after time t is given by the relations;

Vₓ = V₀ × cos(θ₀) = 30 m/s

V_y =  V₀ × sin(θ₀) - g×t

When V_y = 0, we have;

0 =  V₀ × sin(θ₀) - g×t

g×t  =  V₀ × sin(θ₀)  = 10·√109×0.958 = 100 m/s

t = 100/g = 100/10 = 10 s

The time to reach maximum height = 10 s

At 15.0 seconds, we have;

V_y =  V₀ × sin(θ₀) - g×t = 10·√109×0.958  - 10×15 = -50 m/s

Therefore, the projectile is returning at 50 m/s

The magnitude of the velocity =√(30² + 50²) = 10·√34 m/s = 58.31 m/s.

5 0
3 years ago
How did this formula come about? Please show me the formula derivation process
kirill [66]

Answer:

so simple it is a square formula

6 0
3 years ago
How to Measure the mass of a coin using a triple beam balance
Sphinxa [80]

Answer:

https://youtu.be/stW-C7F7QOg

6 0
3 years ago
What are two reasons the period of Venus is shorter than the period of earth
Setler79 [48]

Answer: The planet, named after the Roman goddess of art and beauty, can actually be bright enough to cast shadows on a moonless night. It appears so close to the sun because its orbital radius is smaller than the Earth's, and because it also moves faster than Earth, its orbital period is shorter.

7 0
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