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2 years ago

HELP ASAPPP 10 POINTS

Mathematics

1 answer:

serious [3.7K]2 years ago

6 0

The one on the top should be a right triangle and the bottom one is not

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D^2 + 2d - 8 = 0<br> explain plz

schepotkina [342]

Answer:

d^2 +2d-8=0

first pick two numbers which add up to make +2 and by multiplying those two numbers they should be able to create -8.

so for example 4 and 2

4-2=2

4 x -2= -8

so now factorise:

d^2 +2d-8=0

d^2+4d-2d -8=0

d(d+4)-2(d+4)=0

d+4=0 d-2=0

d=-4 d=2

Step-by-step explanation:

7 0

2 years ago

What is different about the normality requirement for a confidence interval estimate of sigma and the normality requirement for

Harlamova29_29 [7]

Answer:

The normality requirement for a confidence interval estimate of sigma is (stricter) than the normality requirement for a confidence interval estimate of mu. Departures from normality have a (greater) effect on confidence interval estimates of sigma than on confidence interval estimates of mu. That is, a confidence interval estimate of sigma is (less)

8 0

2 years ago

WILL MARK BRAINLIEST!!!!20 POINTS!!!!URGENT!!!

zvonat [6]

Answer:

the firsts third and last one

Step-by-step explanation:

hope this helped

8 0

3 years ago

M3+ 3 m3 + 4 m²<br><br>simplify

Kipish [7]

Answer:

${m}^{3} + {27}^{m} + 4 {m}^{2}$

Step-by-step explanation:

${m}^{3} + {3}^{m 3} + 4 {m}^{2}$

${m}^{3} + {3}^{m \times 3} + 4 {m}^{2}$

${m}^{3} + {3}^{3m} + 4 {m}^{2}$

${3}^{3m} = ({3}^{3} {)}^{m} = {27}^{m}$

➡️ ${m}^{3} + {27}^{m} + 4 {m}^{2}$

5 0

2 years ago

The probability of randomly drawing a red card from a bag that contains red, blue, and green cards is 3/10. What is the probabil

Katarina [22]

If the probability of drawing a red card is 3/10, then if we take this fom a whole, 10/10, we can find the probability of not choosing a red card.
10/10-3/10=7/10

The probability of not drawing a red card is 7/10 or 70%.

7 0

3 years ago