The balanced equation for the reaction is as follows
6H₂O + 6CO₂ ---> C₆H₁₂O₆ + 6O₂
number of moles of CO₂ used - 44 g / 44 g/mol = 1 mol
number of moles of H₂O used - 18 g / 18 g/mol = 1 mol
stoichiometry of CO₂ to H₂O is 6:6 = 1:1
1 mol of CO₂ present and 1 mol of H₂O present therefore they are both fully used up in the reaction of molar ratio 1:1
number of moles of O₂ formed - 32 g/ 32 g/mol = 1 mol
stoichiometry of CO₂:H₂O:C₆H₁₂O₆:O₂ is 6:6:1:6
1 mol of CO₂ has reacted with 1 mol of H₂O to form 1 mol of O₂ and x mol of C₆H₁₂O₆
the number of C₆H₁₂O₆ moles is 1/6th of CO₂ moles used up
since CO₂ moles - 1 mol
therefore C₆H₁₂O₆ moles formed - 1/6 mol = 0.167 mol
mass of glucose formed - 0.167 g x 180 g/mol = 30 g
therefore 30 g of glucose is formed
Answer:
Oxygen gas
Explanation:
Given expression:
CH₃CH₂OH + 3O₂ → 2CO₂ + 3H₂O
Number of moles of oxygen gas = 1 mole
Number of moles of ethanol = 1 mole
Unknown:
The limiting reactant = ?
Solution:
The limiting reactant is the reactant in short supply in a chemical reaction. To find this specie, we always us the number of moles.
From the equation of the reaction:
1 mole of ethanol would require 3 moles of oxygen gas
But we have been given just 1 mole of oxygen gas instead of 3moles.
Therefore, oxygen gas is the limiting reactant.
This is true because the water would have gravitational potential energy that is caused by the water being held back by the dam and the water wanting to flow down.
This can be converted into kinetic energy when given the chance to, such as having a turbine on the dam.
Hope this helps! :)
<span>Answer for the given question is CaBr2.
Although, the given equation requires balancing of by adding one more HBr and one more H2o in resultant. The given equation will product at least one CaBr2. Hence the answer for the given equation is Calcium bromide i.e. CaBr2.</span>
