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saveliy_v [14]
4 years ago
10

Fireworks, KNO3 Give only the names of the elements alphabetically, separating them with commas.

Chemistry
2 answers:
Alborosie4 years ago
4 0
Answer : The  question is to write the elements alphabetically and seperating them with commas.

So in this case for your question of Fireworks , KNO_{3},

The answer will be K, N, O.

You have to just differentiate the elements and write them according to the alphabetical order.
Ksenya-84 [330]4 years ago
4 0

<u>Answer:</u> The elements present are potassium, nitrogen and oxygen.

<u>Explanation:</u>

Elements are defined as the substances in which same type of atoms are present. <u>For Example:</u> Sodium, Chlorine etc.

The chemical formula of the compound used in fireworks is KNO_3

The chemical name for the compound is potassium nitrate.

This compound is formed by the combination of three elements. In 1 mole of potassium nitrate, 1 mole of potassium atom, 1 mole of nitrogen atom and 3 moles of oxygen atoms are present.

Hence, the elements present are potassium, nitrogen and oxygen.

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Acidified water is electrolysed by using carbon electrodes. What is produced
kotegsom [21]

Answer:

Hydrogen gas

Explanation:

During electrolysis of acidified water, H+ ions are reduced to H2 gas at the negative carbon electrode (cathode) and hence hydrogen gas is liberated at cathode.

5 0
3 years ago
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol. Part A If an enzyme increases the
emmasim [6.3K]

Answer:

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

Explanation:

From the given information:

The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.

In this  same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;

Rate factor in the absence of catalyst:

k_1= A*e^{^{^{ \dfrac {- Ea_1}{RT}}

Rate factor in the presence of catalyst:

k_2= A*e^{^{^{ \dfrac {- Ea_2}{RT}}

Assuming the catalyzed reaction and the uncatalyzed reaction are  taking place at the same temperature :

Then;

the ratio of the rate factors can be expressed as:

\dfrac{k_2}{k_1}={  \dfrac {e^{ \dfrac {- Ea_2}{RT} }} { e^{ \dfrac {- Ea_1}{RT} }}

\dfrac{k_2}{k_1}={  \dfrac {e^{[  Ea_1 - Ea_2 ] }}{RT} }}

Thus;

Ea_1-Ea_2 = RT In \dfrac{k_2}{k_1}

Let say the assumed temperature = 25° C

= (25+ 273)K

= 298 K

Then ;

Ea_1-Ea_2 = 8.314 \  J/mol/K * 298 \ K *  In (10^6)

Ea_1-Ea_2 = 34228.92 \ J/mol

\mathbf{Ea_1-Ea_2 = 34.23 \ kJ/mol}

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

8 0
3 years ago
Which type of reaction does this diagram represent?
Citrus2011 [14]

Answer:

Nuclear fission

Explanation:

Because the little particles are being spread out and the two elements are broken apart

8 0
2 years ago
List 5 careers in computer Science
Sliva [168]

Answer:

Software Developer. ...

Database Administrator. ...

Computer Hardware Engineer. ...

Computer Systems Analyst. ...

Computer Network Architect. ...

Explanation:

4 0
4 years ago
Calculate density of aluminum if 27.6cm^3 has a mass of 74.6g
rjkz [21]
First , 27.6 cm^3 is equal to 27.6 ml

Density = mass g / volume cm^3

= 74.6 / 27.6 = ........ g/cm^3
6 0
3 years ago
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