When analyzing inelastic collisions, we need to consider the law of conservation of momentum, which states that the total momentum, p, of the closed system is a constant. In the case of inelastic collisions, the momentum of the combined mass after the collision is equal to the sum of the momentum of each of the initial masses.
p1+p2+...=pf
In our case we only have two masses, which makes our problem fairly simple. Lets plug in the formula for momentum; p=mv.
m1v1+m2v2=(m1+m2)vf
To find the velocity of the combined mass we simply rearrange the terms.
vf=m1v1+m2v2m1+m2
Plug in the values given in the problem.
vf=(3.0kg)(1.4m/s)+(2.0kg)(0m/s)03.0kg+2.0kg
vf=.84m/s
Answer:
173.45 K
Explanation:
This an Adiabatic process because no energy is lost by thermal conduction on expansion. We will be using this Adiabatic condition and ideal gas equation to solve the question.
From idea gas equation;
PV = nRT
-----(1)
where
P is pressure of the gas
V is volume of the gas
n is number of moles
R is gas constant 8.31441 J K-1 mol-1.
T is temperature in Kelvin
For Adiabatic Condition;
----(2)
Substituting equation(1) into equation(2)
Eliminating the constants and simplify with exponent
Making T₂ the subject of the formula;
The temperature when the initial volume has quadrupled ⇒ V₂ = 4V₁
⇒
Since air is diatomic, we assume k = 1.4
∴
T₂ = 173.45 K
The electron won't be traveling because it is as u say "fixed in place".
In ur explanation make sure to use the terms