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lesya692 [45]
4 years ago
9

Which of the following is an electromagnetic wave characteristic which is similar to a particle

Physics
2 answers:
Lady bird [3.3K]4 years ago
8 0
Photoelectric Effect
skelet666 [1.2K]4 years ago
4 0

Answer: The answer is Photoelectric Effect

Explanation:

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An electromagnet is created using a battery, an insulated copper wire and an iron nail. The wire is wrapped around the nail 20 t
Komok [63]

The strength of the electromagnet will be increased with increase in the voltage of the battery and increase in the number of turns of the coil.

Answer: Option C

<u>Explanation: </u>

An electromagnet is generated by passing current through a magnetic material. As per Faraday’s law, magnetic field will be maintained till there is presence of electric flux in the circuit. Thus, like a solenoid, the number of turns of the copper wire on the iron nail will be directly proportional to the strength of the electromagnet.

This is because each turn of the copper wire will act a small region of electromagnet which when added up will lead to increase in the strength of the electromagnet. Similarly,  the electromagnet's strength will also increase when the current flowing in the solenoid is increased.

As the current flow in a circuit is proportional to the battery's voltage used, the increase in the voltage will lead to increase in the flow of current in the solenoid structure. Thus, the increase in voltage as well as the coil's turn number leads to increase in the electromagnet's strength.

7 0
3 years ago
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You place an 8 kg ball on the top of your 2 cm^2 finger tip. Calculate the
Rashid [163]

Answer:

the pressure exerted by the object is 392,000 N/m²

Explanation:

Given;

mass of the object, m = 8 kg

area of your finger, A = 2 cm² = 2.0 x 10⁻⁴ m²

acceleration due to gravity, g = 9.8 m/s²

The pressure exerted by the object is calculated as;

Pressure = \frac{F}{A} = \frac{mg}{A} = \frac{8 \times 9.8}{2\times 10^{-4}} = 392,000 \ N/m^2

Therefore, the pressure exerted by the object is 392,000 N/m²

7 0
3 years ago
A 495-kg dragster accelerates from rest to a final speed of 105 m/s in 395 m, during which it encounters an average frictional f
drek231 [11]

Answer:

Explanation:

According to energy conservation which states that the workdone is equal to change in the system

Workdone = change in kinetic energy + (frictional force * distance)

Workdone = ΔK + fd

Workdone = kf-Ki + fd

Workdone = = 1/2(m(v-u)^2) + fd

Given

Mass m = 495kg

final velocity v = 105m/s

initial velocity = 0m/s

Force f= 1400N

distance d = 395m

Substitute

Workdone = 1/2(495(105-0)^2) + 1400(395)

Workdone = 2,728,687.5+553000

Workdone = 3,281,687.5 Joules

Time = 8.2secs

Power output = Workdone/Time

Power output = 3,281,687.5/8.2

Power output = 885,766.768

Power output = 8.858 * 10^5 watts

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4 years ago
During the Moment of Inertia experiment, a group of students decided to mount a solid sphere on the top of the horizontal disk.
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3 years ago
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B. A sandbar is formed by water. A sand dune is formed by wind.

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