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Softa [21]
2 years ago
14

Mention 10 products made from crude oil​

Chemistry
1 answer:
garri49 [273]2 years ago
4 0

Answer:

"After crude oil is removed from the ground, it is sent to a refinery where different parts of the crude oil are separated into useable petroleum products. These petroleum products include gasoline, distillates such as diesel fuel and heating oil, jet fuel, petrochemical feedstocks, waxes, lubricating oils, and asphalt.

A U.S 42-gallon barrel of crude oil yields about 45 gallons of petroleum products in U.S. refineries because of refinery processing gain. This increase in volume is similar to what happens to popcorn when it is popped."

"What are petroleum products, and what is petroleum used for?

Petroleum products include transportation fuels, fuel oils for heating and electricity generation, asphalt and road oil, and feedstocks for making the chemicals, plastics, and synthetic materials that are in nearly everything we use. Of the approximately 7.21 billion barrels of total U.S. petroleum consumption in 2016, 47% was motor gasoline (includes ethanol), 20% was distillate fuel (heating oil and diesel fuel), and 8% was jet fuel."

Solvents Diesel fuel Motor Oil Bearing Grease

Ink Floor Wax Ballpoint Pens Football Cleats

Upholstery Sweaters Boats Insecticides

Bicycle Tires Sports Car Bodies Nail Polish Fishing lures

Dresses Tires Golf Bags Perfumes

Cassettes Dishwasher parts Tool Boxes Shoe Polish

Motorcycle Helmet Caulking Petroleum Jelly Transparent Tape

CD Player Faucet Washers Antiseptics Clothesline

Curtains Food Preservatives Basketballs Soap

Vitamin Capsules Antihistamines

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How do you balance the equation in number one?
AleksAgata [21]
____NaNO3 + ___PbO --> ___Pb(NO3)2 + ___Na[2]O

To balace the eqaution, you need to have the same number of atoms for each element on both the reactant (left) and product (right) side. 

To start off, you wanna know the number of atoms in each element on both sides, so take it apart:

[reactants]        [product]
Na- 1               Na- 2

N- 1               N- 2(it's 2 because the the subscript [2] is outside of the parenthesis)

O- 4              O- 7 (same reason as above) 

Pb- 1            Pb- 1 

Na is not balanced out, so add a coefficient to make it the same on both sides.In this case, multiply by 2: 

2NaNO3

Now Na is balanced, but the N and O are also effected by this, so they also have to be multiplied by 2 and they become: 

Na- 2             Na- 2 

N- 2              N- 2 (it balanced out) 

O- 7 (coefficient times subscript, plus lone O)  O- 7 (balanced out) 

Pb was already balanced so no need to mess with it, just put a 1 where needed (it doesn't change anything). 

Now to put it back together, it will look like this: 

2NaNO3 + 1PbO --> 1Pb(NO3)2 + 1Na[2]O
3 0
3 years ago
Gravitational forces exerted on any two____in the universe
OleMash [197]

Answer:-

Gravitational forces exerted on any two <em><u>bodies</u></em> in the universe

Hope it helps you...

✅

6 0
2 years ago
1. The molar mass of BeF2
oksano4ka [1.4K]

Answer:

47.01 g/mol is molar mass

8 0
3 years ago
Consider a balloon with volume V. It contains n moles of gas and has an internal pressure of P. The temperature of the gas is T.
Maksim231197 [3]

Answer:

V₂ = 0.6 V.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n is constant, and have different values of P, V and T:

<em>(P₁V₁T₂) = (P₂V₂T₁).</em>

<em></em>

V₁ = V, P₁ = P, T₁ = T.

V₂ = ??? V, ​P₂ = 1.25 P, T₂ = 0.75 T.

<em>∴ V₂ = (P₁V₁T₂)/(P₂T₁) =</em> (P)(V)(0.75 T)/(1.25 P)(T)<em> = 0.6 V.</em>

3 0
3 years ago
Read 2 more answers
An empty container weighs 80.21 g. it is filled with 20.14 mL of an unknown liquid, and the total weight of the container and li
tatiyna

Answer:

1.242 g/mL

Explanation:

Step 1: Given data

Mass of the empty container (m₁): 80.21 g

Mass of the filled container (m₂): 105.22 g

Volume of the unknown liquid (V): 20.14 mL

Step 2: Calculate the mass of the liquid

The mass of the liquid is equal to the difference between the mass of the filled container and the mass of the empty container.

m = m_2 - m_1 = 105.22g - 80.21 g = 25.01 g

Step 3: Calculate the density of the unknown liquid

The density of the liquid is equal to its mass divided by its volume.

\rho = \frac{m}{V} = \frac{25.01g}{20.14mL} = 1.242 g/mL

4 0
3 years ago
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