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natka813 [3]
1 year ago
5

For each of the following, give the sublevel designation, the allowable ml values, and the number of orbitals:

Chemistry
1 answer:
daser333 [38]1 year ago
7 0

The sublevel designation, the allowable ml values, and the number of orbitals are,

For ,n = 2, l = 0 ⇒ sublevel s, ⇒ ml = 0, number of orbitals = 1

<h3>How to calculate electron quantum numbers? </h3>

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n,

2. Subshell number, 0 ≤ l ≤ n − 1, from s, p, d, f, g, h...

3. Orbital energy shift, -l ≤ ml ≤ l

4. Spin, either -1/2 or +1/2

  • So,(a) n = 2, l = 0 ⇒ sublevel s

        -l ≤ ml ≤ l ⇒ ml = 0

         number of orbitals = 1

<h3 /><h3>What are quantum numbers?</h3>

Quantum numbers describe the location of a specific electron within a nucleus. One of four quantum numbers can be used to define each electron in an atom. M S, N, L, M 1, and L A set of rules determines the possible values that can be assigned to each integer.

The position and energy of an electron in an atom are expressed using a set of numbers known as quantum numbers. The four classifications of quantum numbers are: fundamental, azimuthal, magnetic, and spin kinds. Quantum numbers are used to indicate the values of the conserved quantities in a quantum system.

To know more about quantum numbers, refer:

brainly.com/question/5927165

#SPJ4

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What’s the equation to solid calcium oxide reacts with hydrochloric acid to form a solution of calcium chloride and water as it’
meriva

Answer: CaO + 2HCl —> CaCl2 + H2O

Explanation:

3 0
3 years ago
Select the correct answer. which substance in this redox reaction is the oxidizing agent? cu 2agno3 → 2ag cu(no3)2 a. n b. agno3
lana66690 [7]

AgNO₃ will act as the oxidising agent.

<h3><u>For the given chemical equation:</u></h3>

Cu + 2AgNO₃ →  2Ag + Cu(NO₃)₂

Half reactions for the given chemical reaction:

<u>Reducing agent:</u>

Cu → Cu²⁺ + 2e⁻

Copper is a reducing agent because it is losing 2 electrons, which causes an oxidation process.

<u>Oxidising Agent</u>:

Ag⁺ + e⁻ → Ag

The silver ion undergoes a reduction process and is regarded as an oxidizing agent since it is acquiring one electron per atom.

Hence, AgNO₃ is considered as an oxidizing agent and therefore the correct answer is Option B.

<h3><u>Oxidising and Reducing agents</u></h3>
  • An oxidizing agent is a substance that reduces itself after oxidizing another material. It passes through a reduction process in which it obtains electrons and the substance's oxidation state is decreased.
  • A reducing agent is a chemical that oxidizes after reducing another material. It passes through an oxidation process in which it loses electrons and the substance's oxidation state increases.

To know more about the process of Oxidation and Reduction, refer to:

brainly.com/question/4222605

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8 0
8 months ago
Fuel is injected at which state diesel cycle
frez [133]
The Diesel cycle<span> is a combustion process of a reciprocating </span>internal combustion in the cylinders of the engine<span>. In it, </span>fuel<span> is ignited by heat generated during the compression of air in the combustion chamber, into which fuel is then injected and the exhaust from the combustion is pushed out the exhaust pipe or brought out by a turbo </span>
6 0
3 years ago
Molar mass c3h8
maksim [4K]

Answer:

1. 44.11 g

2. 36.03 g

3. 8.08 g

4. 81.7%

5. 18.3%

Explanation:

1. 12.01+12.01+12.01+1.01+1.01+1.01+1.01+1.01+1.01+1.01+1.01=44.11

2. 12.01×3= 36.03

3. 1.01×8= 8.08

4.(36.03/44.11)×100= 81.7%

5. (8.08/44.11)×100= 18.3%

8 0
2 years ago
14) The central iodine atom in the ICl4- ion has __________ nonbonded electron pairs and __________ bonded electron pairs in its
masha68 [24]

Answer:

Two non bonded electron pairs and four bonded electron pairs

Explanation:

An image of the compound as obtained from chemlibretext is attached to this answer.

The ion ICl4- ion, is an AX4E2 ion. This implies that there are four bond pairs and two lone pairs of electrons. As expected, the shape of the ion is square planar since the lone pairs are found above and below the plane of the square. This is clear from the image attached.

7 0
2 years ago
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