The answer to this question is B. Prairie Grass if I'm not mistaken. I hope this helps. ;)
Pretty sure it’s third consumer
HI There!
Which of the following is NOT the same as 13.6 milliliters?- 0.0136 dkL
- 0.0136 L
- 0.136 dL
Answer:<span>0.0136 dkL</span>
The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.
<h3>How do we calculate grams from moles?</h3>
Grams (W) of any substance will be calculated by using their moles (n) through the following equation:
M = molar mass
And moles of the gas will be calculated by using the ideal gas equation as:
P = pressure = 1atm
V = volume = 40L
n = moles = ?
R = universal gas constant = 0.082 L.atm / K.mol
T = temperature = 200K
On putting these values on the above equation, we get
n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles
- Now grams of hydrogen gas will be calculated by using the first equation as:
W = (2.44mol)(2g/mol) = 4.88g
Hence required mass of hydrogen gas is 4.88g.
To know more about ideal gas equation, visit the below link:
brainly.com/question/15046679
#SPJ1
Answer:
a) Warmer
b) Exothermic
c) -10.71 kJ
Explanation:
The reaction:
KOH(s) → KOH(aq) + 43 kJ/mol
It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.
Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.
The enthalpy change for the dissolution of 14 g of KOH is:

<u>Where:</u>
m: is the mass of KOH = 14 g
M: is the molar mass = 56.1056 g/mol

The enthalpy change is:

The minus sign of 43 is because the reaction is exothermic.
I hope it helps you!