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Dmitriy789 [7]
3 years ago
12

Give the coordination number, the charge of the central metal ion, and select the correct name in each coordination compound: A.

Na3[CoCl6] coordination number charge of the central metal ion name B. [Ni(CO)4] coordination number charge of the central metal ion name C. [Ni(NH3)3(H2O)3] (NO3)2 coordination number charge of the central metal ion name
Chemistry
1 answer:
Komok [63]3 years ago
4 0

The correct question is

Give the coordination number, the charge of the central metal ion, and select the correct name in each coordination compound:

Na3[CoCl6]

[Ni(CO)4]

[Ni(NH3)3(H2O)2] (NO3)2

Answer:

See explanation for details

Explanation:

Na3[CoCl6]

Name: Sodium hexacholorocobalt III

Charge on the complex: -3

Central metal ion name : cobalt III

coordination number: 6

[Ni(CO)4]

Name: tetracarbonyl nickel (0)

Charge on the complex: 0

Central metal ion name : nickel (0)

coordination number: 4

[Ni(NH3)3(H2O)2] (NO3)2

Name: Diaquatriaminenickel II nitrate

Charge on the complex: +2

Central metal ion name : nickel (+2)

coordination number: 5

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Which of the following is NOT the same as 13.6 milliliters?
rjkz [21]
HI There! 

Which of the following is NOT the same as 13.6 milliliters?- 0.0136 dkL
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Answer:<span>0.0136 dkL</span>
4 0
3 years ago
Calculate how many grams of hydrogen can be burned if 40. liters of oxygen at 200. k and 1.0 atm. show work pls.
Wittaler [7]

The grams of hydrogen gas can be burned if 40. liters of oxygen at 200. k and 1.0 atm is 4.88 grams.

<h3>How do we calculate grams from moles?</h3>

Grams (W) of any substance will be calculated by using their moles (n) through the following equation:

  • n = W/M, where

M = molar mass

And moles of the gas will be calculated by using the ideal gas equation as:

  • PV = nRT, where

P = pressure = 1atm

V = volume = 40L

n = moles = ?

R = universal gas constant = 0.082 L.atm / K.mol

T = temperature = 200K

On putting these values on the above equation, we get

n = (1)(40) / (0.082)(200) = 2.439 = 2.44 moles

  • Now grams of hydrogen gas will be calculated by using the first equation as:

W = (2.44mol)(2g/mol) = 4.88g

Hence required mass of hydrogen gas is 4.88g.

To know more about ideal gas equation, visit the below link:

brainly.com/question/15046679

#SPJ1

7 0
3 years ago
Upon adding solid potassium hydroxide pellets to water the following reaction takes place: KOH(s) → KOH(aq) + 43 kJ/mol Answer t
nekit [7.7K]

Answer:

a) Warmer

b) Exothermic

c) -10.71 kJ

Explanation:

The reaction:

KOH(s) → KOH(aq) + 43 kJ/mol

It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.

Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.

The enthalpy change for the dissolution of 14 g of KOH is:

n = \frac{m}{M}

<u>Where:</u>

m: is the mass of KOH = 14 g

M: is the molar mass = 56.1056 g/mol

n = \frac{m}{M} = \frac{14 g}{56.1056 g/mol} = 0.249 mol

The enthalpy change is:

\Delta H = -43 \frac{kJ}{mol}*0.249 mol = -10.71 kJ

The minus sign of 43 is because the reaction is exothermic.

I hope it helps you!

5 0
3 years ago
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