Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
Answer:
Step-by-step explanation:
12x+2y=36
2y=36-12x
5x+36-12x=22
7x=14
x=2
2y=36-12(2)
2y=12
y=6
btw,next time, please do not include words like(failing ,exam,test,etc) in your question,otherwise, the question might be deleted.
B = 0.26 h - 18.85,
where b is the length of the radius bone and h is the height.
To find the equation for height of a woman, you can solve the equation for h.
0.26 h = b + 18.85
h = ( b + 18.85 ) / 0.26
h = ( 100 b + 1,885 ) / 26
Then you can plug in the length of the radius bone in this equation.
The total number of arrangements for all of them to be women is:
C(7, 4) because the order does not matter; we'd still have the same arrangements.
Now, we can simplify this:




Now, the total number of arrangements, without restriction, is simply: C(12, 4) because we don't care who we pick.