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Lena [83]
3 years ago
5

Which doesn't belong in the group?

Chemistry
1 answer:
ivann1987 [24]3 years ago
6 0
Magnetite because it is an iron ore while the rest are magnets or have to do with magnetism.
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Sucrose is very soluble in water. at 25◦c, 211.4 grams of sucrose will dissolve in 100 g of water. given that the density of the
stiv31 [10]
Molarity of solution is mathematically expressed as,
M = \frac{x\text{weight of solute(g)}}{\text{Molecular weight X Volume of solution(l)}}

We know that volume = mass/density
Given: mass of solution = 100 g, Density = 1.34 g/ml
∴ volume = 100/1.34 = 88.49 ml = 0.08849 l

Also, we know that molecular weight of sucrose = 342.3 g/mol
 ∴M = \frac{x\text{211.4}}{\text{342.3 X 0.08849}}
       = 6.979 M

Thus, molarity of solution is 6.979 M
8 0
3 years ago
In Chromium-53, the "53" represents the
alina1380 [7]

Answer:

The differemt isotopes that differ in atomic mass

Explanation:

4 0
2 years ago
Read 2 more answers
Jonas mixes citric acid with baking soda. How does he know the reaction is endothermic?
Kipish [7]

Answer:

D. The temperature of the the solution increases

Explanation:

Endothermic. Endo means in and thermic means a temperature, so Endothermic means the taking in of an temperature and the only answer choices that deal with temperature is,A and D. If it absorbs temperature it's going to rise.

6 0
3 years ago
In the molecules below, areas that have a partial negative charge are pink and areas that have a partial positive charge are blu
Kaylis [27]

Answer:

Dipole-dipole interactions

Step-by-step explanation:

Each molecule consists of <em>two different elements</em>.

Thus, each molecule has permanent <em>bond dipoles</em>.

The dipoles do not cancel, so the attractive forces are dipole-dipole attractions.

"Covalent bonds" is <em>wrong,</em> because there are no bonds between the two molecules.

There are dipole-induced dipole and London dispersion forces, but they are much weaker than the dipole-dipole attractions.

4 0
3 years ago
Plz plz plz plz answer I have not much time<br> Fourth option is a neutral boron atom.
jarptica [38.1K]
A is correct hope this helps
4 0
3 years ago
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