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Leona [35]
3 years ago
13

Hydrogen reacts with iodine to form hydrogen iodide: H2[g] + 12[g] = 2H1[g] The

Chemistry
1 answer:
ELEN [110]3 years ago
6 0

Answer:

follow my instagram to help you with your school work in general

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Your dad is working on creating a brick border for the lake in your backyard each brick has a mass of 100 g and a volume of 20 c
wel

Answer:

5000kg/m³

Explanation:

density=mass/volume

d=m/v

d=100/20

=5g/cm³

g/cm³*1000=kg/m³

5g/m³*1000=5000kg/m³

4 0
3 years ago
Read 2 more answers
Can someone help me with number 1 and 2 plz!
GalinKa [24]

Answer:

1) 0 N

2) 8 N

Explanation:

The net force is the sum of all of the forces acting on the object.

For question 1, we can see that there is a force of 5 N acting to the right and 5 N acting to the left.  If we define the right to be positive and the left to be negative, then the net force equals:

Fnet = 5N - 5N = 0 N

Therefore, the net force in question 1 is 0 N.

For question 2, the process is very similar.  We want to find the sum of the forces acting on the object.  In this case, there are forces of 3 N and 5 N acting to the right.

Fnet = 3 N + 5 N = 8 N

Therefore, the net force in question 2 is 8 N.

Hope this helps!

3 0
3 years ago
Help!!!!
V125BC [204]

Answer:D and C sorry if im wrong

Explanation:

8 0
3 years ago
Read 2 more answers
A light bulb has a resistance of 96.8 Ω. What current flows through the bulb when it is connected to a 120 V source of electrica
Finger [1]

Answer:

I = 1.23 A

Explanation:

Given that,

The resistance of the lightbulb, R = 96.8 Ω

Voltage, V = 120 V

We need to find the current flows through the lightbulb. Let the current be I. We can use the ohm's law to find it i.e.

V=IR\\\\I=\dfrac{V}{R}\\\\I=\dfrac{120}{96.8}\\\\I=1.23\ A

So, the current flows through the bulb is 1.23 A.

8 0
3 years ago
A 25.0 mL sample of an acetic acid solution is titrated with a 0.175 M NaOH solution. The equivalence point is reached when 26.6
joja [24]

<u>Answer:</u> The concentration of CH_3COOH comes out to be 0.16 M.

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is CH_3COOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=25mL\\n_2=1\\M_2=0.175M\\V_2=26.6mL

Putting values in above equation, we get:

1\times M_1\times 25=1\times 0.175\times 26.6\\\\M_1=0.1862M

Hence, the concentration of CH_3COOH comes out to be 0.1862 M.

4 0
3 years ago
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