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3 years ago

Hydrogen reacts with iodine to form hydrogen iodide: H2[g] + 12[g] = 2H1[g] The

Chemistry

1 answer:

ELEN [110]3 years ago

6 0

Answer:

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A certain second-order reaction (B→products) has a rate constant of 1.30×10−3 M−1⋅s−1 at 27 ∘C and an initial half-life of 224 s

soldier1979 [14.2K]

Answer:

$\large\boxed{\large\boxed{0.291M}}$

Explanation:

By definition one half-life is the time to reduce the initial concentration to half.

For a second order reaction the rate law equations are:

$\dfrac{d[B]}{dt}=-k[B]^2$

$\dfrac{1}{[B]}=\dfrac{1}{[B]_0}+kt$

The half-life equation is:

$t_{1/2}=\dfrac{1}{k[A]_0}$

Thus, substitute the rate constant $1.30\times 10^{-3}M^{-1}\cdot s^{-1}$ and the half-life time 224s to find [A]₀:

$224s=\dfrac{1}{1.30\times10^{-3}M^{-1}\cdot s^{-1}[A]_0}$

$[A]_o=0.291M$

7 0

3 years ago

Let us assume that cu(oh)2(s) is completely insoluble, which signifies that the precipitation reaction with naoh(aq) (presented

yKpoI14uk [10]

Answer: (0.150 L) x (0.0240 M Fe{3+}) x (3 mol OH{-} / 1 mol Fe{3+}) / (1.39 M NaOH) = 0.00777 L = 7.77 mL NaOH

6 0

4 years ago

The molecular ion is not visible in the mass spectrum of 2-chloro-2- methylpropane. At what m/z value would the molecular ion be

pochemuha

Answer: hello the complete question is attached below

Visibility of molecular ion = m/z value of 77

Explanation:

For The molecular ion to be visible, it has to be at an m/z value of 77 and this is because molecular ions will have an m/z ratio = molecular mass of given molecule in most cases but not always in all cases.

And the visibility is possible after the removal of CH₃ ion.

ii) Evidence in the mass spectrum that suggests peak at m/z = 77

attached below

5 0

3 years ago

Chemical formula of tetraphosphurus octasulfide

Firlakuza [10]

Answer:

Explanation: Does any of this look right? To be honest I just looked it up.

6 0

4 years ago

What are dependent variables?

Dmitry [639]

I think It's a value that depends on another

3 0

3 years ago

Read 2 more answers