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2 years ago

Find the perimeter.

Mathematics

1 answer:

ad-work [718]2 years ago

4 0

Answer:

22v^2 + 5v - 4

Step-by-step explanation:

5v^2 + 9v - 11 + v - 7 + 17v^2 -5v +14

22v^2 + 5v - 4

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$6,000 dollars is invested in two different accounts earning 3% and 5% interest. at the end of one year, the two accounts earned

Anettt [7]

Answer-

$2000 were invested at 5%

Solution-

Let x amount of money was invested at 5% and (6000-x) amount was invested as 3%

We know that,

$i=\dfrac{P\cdot r\cdot t}{100}$

Putting the values,

$i_1=\dfrac{P_1\cdot r_1\cdot t}{100}$

$i_1=\dfrac{x\cdot 5\cdot 1}{100}=\dfrac{5x}{100}$

And

$i_2=\dfrac{P_2\cdot r_2\cdot t}{100}$

$i_2=\dfrac{(6000-x)\cdot 3\cdot 1}{100}=\dfrac{3(6000-x)}{100}$

According to the question,

$\Rightarrow \dfrac{5x}{100}+\dfrac{3(6000-x)}{100}=220$

$\Rightarrow \dfrac{5x+3(6000-x)}{100}=220$

$\Rightarrow 5x+3(6000-x)=22000$

$\Rightarrow 5x+18000-3x=22000$

$\Rightarrow 5x-3x=22000-18000$

$\Rightarrow 2x=4000$

$\Rightarrow x=2000$

Therefore, $2000 were invested at 5%

8 0

3 years ago

Read 2 more answers

If each cup cost 0.50 cents and there is $127.50 collected how much cups are there

Digiron [165]

Answer: Hello, Before I answer this question... I need to say.. DO NOT SEARCH THAT LINK, It is a scam. Those are BAD PEOPLE!!!

anyway...The Answer to this question is $127.50 divided by $0.50 which equals 255 cups in total. Mark me as Brainliest! :) :) :)

Step-by-step explanation:

7 0

2 years ago

Describing words? beginning with "s"? i need a word that describes someone nicely that begins with the letter "s"

Helga [31]

Sweet? Sweet is a nice word to say to people or about people.

3 0

3 years ago

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a principal of $700 is invested in an account at 6% per year compounded annually what is the total amount of money in the accoun

pishuonlain [190]

Answer:

$936.76

Step-by-step explanation:

6 0

3 years ago

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Consider the differential equation: dy/dx = (y-2)(x^2+1)

Klio2033 [76]

Answer:

Step-by-step explanation:

Given,

$\dfrac{dy}{dx}=(y-2)(x^2+1)$ ...(i)

Differentiating w.r. to x.

$\dfrac{d^2y}{dx^2}= (y-2)(2x)+ (x^2+1)\dfrac{dy}{dx}$

From equation (1)

$\dfrac{d^2y}{dx^2}= (y-2)(2x)+ (x^2+1)^2(y-2)$

Now, at the point (1,3)

$\dfrac{d^2y}{dx^2}= (3-2)(2\times 1)+ (1^2+1)^2(3-2)$

$\dfrac{d^2y}{dx^2}=6$

3 0

3 years ago