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2 years ago

Can someone help me with these questions please?

Physics

1 answer:

Alenkinab [10]2 years ago

8 0

Answer:

pang anong grade po yan kasi grade 4 palang po

kasi ako

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How much total work is done by the force in lifting the elevator from 0.0 m to 9.0 m?

aksik [14]

The total work is

(mass of the elevator, kg) x (9.8 m/s²) x (9.0 m) Joules .

8 0

3 years ago

A 30.0 kg dolphin decelerates from 12.0 to 7.00 m/s in 2.60 s to join another dolphin in play. What average force (in N) was exe

Crazy boy [7]

Answer:

Force is 57.69 N to the opposite direction of motion of dolphin.

Explanation:

We have force is the product of mass and acceleration.

That is

Force = Mass x Acceleration

F = ma

Mass of dolphin, m = 30 kg

We have equation of motion, v = u + at

Final velocity, v = 7 m/s

Initial velocity, u = 12 m/s

Time, t = 2.60 s

Substituting

7 = 12 + a x 2.6

a = -1.92 m/s²

Force, F = 30 x -1.92 = -57.69 N

So the force is 57.69 N to the opposite direction of motion of dolphin.

7 0

2 years ago

If there is no slipping, a frictional force must exist between the wheels and the ground. in what direction does the frictional

djyliett [7]

The frictional force is always act in opposite direction of motion. if wheels is moving in +x axis or right then the f force is act in -x or left

8 0

3 years ago

A ball is thrown upward from the ground with an initial speed of 22.0 m/s; at the same instant, another ball is dropped from a b

Vikki [24]

They will be together in 8 minutes

3 0

3 years ago

A silver sphere with radius 1.3611 cm at 23.0°C must slip through a brass ring that has an internal radius of 1.3590 cm at the s

Readme [11.4K]

Answer:

The temperature must the ring be heated so that the sphere can just slip through is 106.165 °C.

Explanation:

For brass:

Radius = 1.3590 cm

Initial temperature = 23.0 °C

The sphere of radius 1.3611 cm must have to slip through the brass. Thus, on heating the brass must have to attain radius of 1.3611 cm

So,

Δ r = 1.3611 cm - 1.3590 cm = 0.0021 cm

The linear thermal expansion coefficient of a metal is the ratio of the change in the length per 1 degree temperature to its length.

Thermal expansion for brass = 19×10⁻⁶ °C⁻¹

Thus,

$\alpha=\frac {\Delta r}{r\times \Delta T}$

Also,

$\Delta T=T_{final}-T_{Initial}$

So,

$19\times 10^{-6}=\frac {0.0021}{1.3290\times (T_{final}-23.0)}$

Solving for final temperature as:

$(T_{final}-23.0)=\frac {0.0021}{1.3290\times 9\times 10^{-6}}$

Final temperature = 106.165 °C

5 0

3 years ago