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2 years ago

Can someone help me with these questions please?

Physics

1 answer:

Alenkinab [10]2 years ago

8 0

Answer:

pang anong grade po yan kasi grade 4 palang po

kasi ako

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A typical nuclear fission power plant produces about 1.00 GW of electrical power. Assume the plant has an overall efficiency of

mamaluj [8]

Answer:

mass consumed by 235U each day = 2 kg

Explanation:

electrical power produced = 1 GW = 1 × 10⁹ × (6.24151 × 10¹⁸ ) eV

= 6.24151× 10²¹ MeV/s

thermal energy = 0.420 * 250 = 105 MeV

$\dfrac{1 GW}{150 MeV}= \dfrac{6.24151\times 10^{21}}{105}$

= 5.94 × 10¹⁹ fission/second

=5.94 × 10¹⁹× 24 × 60 ×60)

= 5.13 × 10²⁴ fission/day

mu = 235.04393 × 1.660× 10 ⁻²⁷ = 390.1729× 10⁻²⁷ Kg

M = mu ×5.13 × 10²⁴

= 390.1729× 10⁻²⁷ ×5.13 × 10²⁴

M = 2 kg(approx.)

mass consumed by 235U each day = 2 kg

3 0

3 years ago

A planetâs moon revolves around the planet with a period of 39 Earth days in an approximately circular orbit of radius of 4.8Ã10

Alchen [17]

Answer:

v = 895 m/s

Explanation:

Time period is given as 39 Earth Days

$T = 39 days \times 24 hr \times 3600 s$

$T = 3369600 s$

now the radius of the orbit is given as

$r = 4.8 \times 10^8 m$

so the total path length is given as

$L = 2 \pi r$

$L = 2\pi (4.8 \times 10^8)$

$L = 3.015 \times 10^9$

now the speed will be given as

$v = \frac{L}{T}$

$v = \frac{3.015 \times 10^9}{3369600}$

$v = 895 m/s$

7 0

4 years ago

In the diagram of the conical pendulum below, which number (1, 2, 3, or 4) represents the angle θ used in the conical pendulum e

Mama L [17]

Step 1: Look in your book or online for the conical pendulum equation.

Step 2: Look at the drawing and see which angle is involved in the equation.

Answer: It's Angle #2 in your drawing.

8 0

3 years ago

Which units are used to measure force?

shtirl [24]

Newtons are used to measure force

7 0

4 years ago

Read 2 more answers

The greatest ocean depths on earth are found in the Marianas Trench near the Philippines, where the depth of the bottom of the t

kompoz [17]

Answer:

103063860 Pa

Explanation:

$\rho$ = Density of seawater = 1030 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth at which pressure is being measured = 10.2 km

The gauge pressure is given by

$p=\rho gh\\\Rightarrow p=1030\times 9.81\times 10.2\times 10^3\\\Rightarrow p=103063860\ Pa$

Therefore, the gauge pressure at a depth of 10.2 km is 103063860 Pa

3 0

3 years ago