The visible surface of the Sun, which is also the deepest layer we can see with our eyes, is in which region of the Sun?

Energy of motion is known as what energy

GaryK [48]

Kinetic Energy = Energy of Motion

3 0

3 years ago

If a large housefly 2.4 m away from you makes a noise of 47.0 dB, what is the noise level (in dB) of 5400 flies at that distance

dem82 [27]

Answer:

the noise level of 5400 flies is equal to 84.32 dB

Explanation:

Noise made by house flies = 47 dB from the distance of 2.4 m

to calculate the noise of 5400 flies at a distance of 2.4 m.

the intensity of noise

$10 log_{10}(\dfrac{I}{I_0}) = 47 dB$

now, I' = 5400 I₀

= $10 log_{10}(\dfrac{5400 I}{I_0})$

= $10 [log_{10}[5400] +log_{10}(\dfrac{I}{I_0}))$

= 10 ( 3.732 + 4.7 )

= 84.32 dB

hence, the noise level of 5400 flies is equal to 84.32 dB

4 0

3 years ago

13 points!

skelet666 [1.2K]

I think it may be C!

4 0

3 years ago

Read 2 more answers

On Earth, the number flux of solar neutrinos from the p-p chain is:

Nataly [62]

Answer:

Explanation:

The volume of the tank = 50 kton

50 kton = 5 × 10⁷ kg

Since 18 grams of water will contain: 10 electrons × 6.023 × 10²³

Then;

5× 10⁷ kg will contain $( \dfrac{5 \times 10^7 \times 10^3}{18}) \times 10 \times 6.023 \times 10^{23}$

= 1.67 × 10³⁴ electrons

(b)

Suppose:

$f_{neutrino} = \dfrac{2f_o}{26.2 MeV} = 6.7\times 10^{10} \ s^{-1} cm^{-2}$

Then;

10⁻⁶ of $f_{neutrino} = 6.7 \times 10^{10} \times 10^{-6} \ s^{-1} cm^{-2}$

$=6.7 \times 10^{4}\ s^{-1} cm^{-2}$

Thus, the number of high energy neutrinos which will interact with water is:

= $6.7 \times 10^4 \times \sigma$

= $6.7 \times 10^4 \times 10^{-43}$

= $6.7 \times 10^{-39} s^{-1}$

For 1.67 × 10³⁴ electrons, the detection rate is:

$6.7 \times 10^{-39} \times 1.67 \times 10^{34}$

$= 11.19 \times 10^{-5} \ s^{-1}$

= 9.668 per day

3 0

3 years ago

How will air resistance affect a falling object?

Greeley [361]

<span>Air resistance, also called drag, acts upon a falling body by slowing the body down to the point where it stops accelerating, and it falls at a constant speed, known as the terminal velocity of a falling object. Air resistance depends on the cross-sectional area of the object, which is why the effect of air resistance on a large flat-surfaced object is much greater than on a small, stream-lined object.</span>

6 0

3 years ago