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Zolol [24]
3 years ago
10

The visible surface of the Sun, which is also the deepest layer we can see with our eyes, is in which region of the Sun?

Physics
1 answer:
Nina [5.8K]3 years ago
5 0
It is the photosphere
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A speedboat moves on a lake with initial velocity vector v1,x = 8.57 m/s and v1,y = -2.61 m/s, then accelerates for 6.67 seconds
KengaRu [80]
First, you find the velocity at each component. The general equation is:

a = (v2 - v1)/t

a,x = (v2,x - v1,x)/t
-0.105 = (v2,x - 8.57)/6.67
v2,x = 7.87 m/s

a,y = (v2,y - v1,y)/t
0.101 = (v2,y - -2.61)/6.67
v2,y = -1.94 m/s

To find the final speed, find the resultant velocity by taking the hypotenuse.

v^2 = (v2,x)^2 + (v2,y)^2
v^2 = (7.87)^2 + (-1.94)^2
v = 8.1 m/s
3 0
3 years ago
Consider what happens at the moment when the block leaves the surface of the globe. Which of the following statements are correc
erma4kov [3.2K]

Answer:

Statement 1 and 3 are correct.

Explanation:

1. The mass moves  downward, so the net acceleration of the block is straight downward.

2.The mass is sliding through the globe, so only the force of gravity is acting on the mass which pulls it in downward direction. The force of gravity has two components [mg sin∅] and [mg cos∅].

6 0
3 years ago
Read 2 more answers
How many electrons are in the third energy level of a calcium atom
lidiya [134]
There are 8 electrons in the third energy level of Calcium atom.  
4 0
2 years ago
Read 2 more answers
19. A person pushes with 6.0 N for 4.0 seconds on a 2.0 kg object.
hram777 [196]

Answer:24NS

Explanation:

Impulse=force x time

Impulse=6 x 4

Impulse=24NS

5 0
3 years ago
Oil at 150 C flows slowly through a long, thin-walled pipe of 30-mm inner diameter. The pipe is suspended in a room for which th
chubhunter [2.5K]

Answer:

<em>1.01 W/m</em>

Explanation:

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

From the above,<em> we assumed that the pipe wall and the oil are in thermal equilibrium</em>.

area of the pipe per unit length A = \pi r ^{2} = 7.069*10^{-4} m^2/m

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130 = <em>1.01 W/m</em>

4 0
3 years ago
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