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Phantasy [73]
4 years ago
10

A standing wave is the result of: refraction diffraction reflection resonance

Physics
2 answers:
natita [175]4 years ago
3 0
A standing wave is the result of a reflection. 
dusya [7]4 years ago
3 0
The answer is relection
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Angle of reflection <br>​
Fittoniya [83]

The angle of reflection equals the angle of Incidence

Explanation:

The Law Of Reflection

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3 years ago
When you hear an ambulance siren, it alternates between high and low tones, depending on the frequency of sound waves. this is c
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<span>Frequency of a sound wave is called the pitch. Higher frequencies have a higher pitch and lower frequencies have the opposite. When an ambulance travels by a listener, the frequencies are oscillating rapidly and causing the shrill, loud sounds that emanate from the sirens.</span>
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4 years ago
A spiral spring has a length of 14 cm when a force of 4 N is hung on it. A force of 6 N extends
stira [4]

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Explanation:

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5 0
2 years ago
You walk 60m east and then 20m at 20 degrees south of west. What is your displacement?
stich3 [128]
Let north and east be posetive
Y=20sin20
=6.840402867 south
X=20cos20
18.79385243 west
Net horizontal components=60+(-18.79)
=41.20614758m
Net vertical=-6.84040267
X^2=41.20614758^2+(-6.684040267)^2
√x^2 =√1744.73771m
x=41.77m
5 0
3 years ago
A model rocket fired vertically from the ground ascends with a constant vertical acceleration of 52.7 m/s2 for 1.41 s. its fuel
olya-2409 [2.1K]
For rectilinear motions, derived formulas all based on Newton's laws of motion are formulated. The equation for acceleration is

a = (v2-v1)/t, where v2 and v1 is the final and initial velocity of the rocket. We know that at the end of 1.41 s, the rocket comes to a stop. So, v2=0. Then, we can determine v1.

-52.7 = (0-v1)/1.41
v1 = 74.31 m/s

We can use v1 for the formula of the maximum height attained by an object thrown upwards:

Hmax = v1^2/2g = (74.31^2)/(2*9.81) = 281.42 m

The maximum height attained by the model rocket is 281.42 m.

For the amount of time for the whole flight of the model rocket, there are 3 sections to this: time at constant acceleration, time when it lost fuel and reached its maximum height and the time for the free fall.

Time at constant acceleration is given to be 1.41 s. Time when it lost fuel covers the difference of the maximum height and the distance travelled at constant acceleration.

2ax=v2^2-v1^2
2(-52.7)(x) = 0^2-74.31^2
x =52.4 m (distance it covered at constant acceleration)
Then. when it travels upwards only by a force of gravity,
d = v1(t) + 1/2*a*t^2
281.42-52.386 = (0)^2+1/2*(9.81)(t^2)
t = 6.83 s (time when it lost fuel and reached its maximum height)

Lastly, for free falling objects, the equation is
t = √2y/g = √2(281.42)/9.81 = 7.57 s

Therefore, the total time= 1.41+6.83+7.57 = 15.81 s

6 0
3 years ago
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