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Phantasy [73]
3 years ago
10

A standing wave is the result of: refraction diffraction reflection resonance

Physics
2 answers:
natita [175]3 years ago
3 0
A standing wave is the result of a reflection. 
dusya [7]3 years ago
3 0
The answer is relection
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Someone help please by providing work and answers please :)
cupoosta [38]
There are two ways to solve this. The longer way is to use those equations to calculate numbers for total distance.

The easier way is to find the area under the graph. That's right, AREA UNDER VELOCITY-TIME graph is the TOTAL DISTANCE travelled!

it's a shortcut.

Let's split up the area into a triangle and rectangle:

Triangle = 0.5(4-0)(10-0) = 20 m
Rectangle = (6-4)(10-0) = 20 m

Total distance = 40 m!
6 0
3 years ago
Find electric field at point p which is a distance l away from the both +q and -q
denis-greek [22]

Answer:

\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }

Where

  • q is the charge
  • r is the distance
  • E is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }

F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

⇒

F1+F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

8 0
3 years ago
The state of matter that has low thermal expansion​
leonid [27]

Answer:

Matter

Explanation:

Because it is solid

6 0
3 years ago
Read 2 more answers
A person can swim at 9 m/s. How long will it take them to swim 35 m
IRISSAK [1]

Answer:

v =  \frac{d}{t}   \\ t =  \frac{d}{v}  \\  =  \frac{35}{9} sec

5 0
2 years ago
John pushes his bed to the left overcoming the force of friction. On the free-body diagram below, which force represents the fri
mamaluj [8]

Answer:

<em>Force B</em>

Explanation:

<u>Friction Force </u>

It's a force that appears when an object is tried to move on a rough surface. There are two cases: when the object is at rest, we have the friction static coefficient and when the object is already moving, we have the dynamic coefficient. The static coefficient is usually greater than the second because it's harder to overcome the friction when the object is at rest.

We are told that John pushes the bed to the left with enough force to overcome the force of friction. If the movement is intended to be to the left side, the friction force appears to the right, since it always opposes to the movement. Thus the force B is the one who represents the friction force in this situation

6 0
3 years ago
Read 2 more answers
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