Answer:
its c, y = one eighthx2 + 1
Step-by-step explanation:
Answer: c.+dhf+2-4= 6)
Step-by-step explanation: Hope this helps!
Answer:
The area of given function is 5.67 unit²
Step-by-step explanation:
Given function f(x) as :
f(x) = 2 x² + 3
The interval in which f(x) lies [ 0 , 2 ]
Let The area for the curve = A
Or , A = 
Or, A = 
Or, A = 
or, A = ![\frac{1}{2} [2( \frac{2^{3}-0^{3}}{3})] + \frac{1}{2}[3 (2-0)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5B2%28%20%5Cfrac%7B2%5E%7B3%7D-0%5E%7B3%7D%7D%7B3%7D%29%5D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5B3%20%282-0%29%5D)
or, A =
(
+ 6 )
Or, A =
× 
∴ A = 5.67 unit²
Hence The area of given function is 5.67 unit² Answer