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Nata [24]
2 years ago
9

Determine the kinetic energy of a 1000-kg roller coaster car that is moving with a speed of 20.0 m/s

Physics
1 answer:
erastovalidia [21]2 years ago
8 0

Answer:

2*10^{5}

Explanation:

Kinetic energy = \frac{1}{2} M V^{2}

M is mass

V is velocity

K.E. = \frac{1}{2} * 1000 * 20^{2}  

K.E. = 2*10^{5}

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katrin2010 [14]

Answer:35.2 ft

Explanation:

Given

height of stick =4 ft

shadow length =2.8 ft

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tan\theta =\frac{h}{24.64}

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8 0
3 years ago
3. What is the gravitational force between a 70 kg physics student and her 1 kg textbook, at a distance of 1 meter? (This number
Rina8888 [55]

ANSWER

\begin{equation*} 4.67*10^{-9}\text{ }N \end{equation*}

EXPLANATION

Parameters given:

Mass of the student, M = 70 kg

Mass of the textbook, m = 1 kg

Distance, r = 1 m

To find the gravitational force acting between the student and the textbook, apply the formula for gravitational force:

F=\frac{GMm}{r^2}

where G = gravitational constant

Therefore, the gravitational force acting between the student and the textbook is:

\begin{gathered} F=\frac{6.67430*10^{-11}*70*1}{1^2} \\  \\ F=4.67*10^{-9}\text{ }N \end{gathered}

That is the answer.

6 0
1 year ago
A child on a skateboard experiences a 75 N force with an acceleration of 1.5 m/s2.
cupoosta [38]

Answer:

The mass of the child + skateboard is 50 kg

Explanation:

In this problem, we can apply Newton's second law:

F = ma

where

F is the net force on a system

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a is the acceleration of the system

In this problem, our system is the child + the skateboard. The net force on them is

F = 75 N

and their acceleration is

a=1.5 m/s^2

So we can re-arrange the equation above to find their combined mass:

m=\frac{F}{a}=\frac{75}{1.5}=50 kg

3 0
3 years ago
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quester [9]

Answer:

C

Explanation:

7 0
3 years ago
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