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Tju [1.3M]
2 years ago
7

What is the length of side s of the square shown below?

Mathematics
1 answer:
zaharov [31]2 years ago
8 0

Answer:

A.\: 4 \sqrt{2}

Step-by-step explanation:

\sin \: 45 \degree =  \frac{s}{8}  \\  \\  \implies \:  \frac{1}{ \sqrt{2} }  = \frac{s}{8}  \\  \\  \implies \: s =  \frac{8}{ \sqrt{2} }  =  \frac{8 \sqrt{2}}{2}  \\  \\  \implies \:  \huge \: s = 4 \sqrt{2}

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What value added to x2 − 8x would complete the square?
Mazyrski [523]
X^2 - 8x  = (x - 4)^2 - 16

we add 16 to  give   x^2 - 8x + 16  which is a perfect square 

x^2 - 8x + 16  = (x - 4)^2

answer is 16
7 0
3 years ago
Read 2 more answers
Solve linear equation 1/4 x + 18 = X
Anton [14]

Answer:

24

Step-by-step explanation:

1 / 4 x + 18 = x

x / 4 + 18 = x

x = x / 4 + 18

x - x / 4 = 18

( 4x / 4 ) - ( x/4 ) = 18

( 4x - x ) / 4 = 18

3x / 4 = 18

3x = 18 * 4

x = ( 18 * 4 ) / 3

  = 6 * 4

x = 24

3 0
2 years ago
I need question a and b done pls help
FrozenT [24]

Answer:

A. 5

B. 12

Step-by-step explanation:

What you do is you substitute -2 into the a and the 3 into the b.

a. 3(-2)^2-5(3)+8                       b. 2/3(3)-5(-2)

3(4)-15+8                                   2-(-10)

12-15+8                                      12 is your answer.

-3+8

5 is your answer.

8 0
3 years ago
Read 2 more answers
How can you use an equation to make a prediction from a pattern?
Vanyuwa [196]
Upon formation of an equation from a given pattern, we know how the variables in the patter are related. Using the equation, we can find the value of one of the missing variables if the rest are known and also predict the values of the pattern at given conditions.
An example:
y = 2x + 5
if we are to predict the value of y at x = 3, we simply substitute 3 into x
y = 2(3) + 5
= 11
8 0
3 years ago
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Evaluate $\dfrac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}$.
Pavlova-9 [17]
<h3>Answer:  4</h3>

========================================================

Work Shown:

\frac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}\\\\\frac{2\sqrt{36*2}}{\sqrt{4*2}+\sqrt{2}}\\\\\frac{2\sqrt{36}*\sqrt{2}}{\sqrt{4}*\sqrt{2}+\sqrt{2}}\\\\\frac{2*6*\sqrt{2}}{2*\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{2\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{3\sqrt{2}}\\\\\frac{12}{3}\\\\4

Note in step 2, I factored each number in the square root to pull out the largest perfect square factor. From there, I used the rule that \sqrt{A*B} = \sqrt{A}*\sqrt{B} to break up the roots.

8 0
2 years ago
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