Ask question

Ask question

All categories

3 years ago

11

What is the common difference between successive terms in the sequence?

2 answers:

anzhelika [568]3 years ago

7 0

Look at each term. How does the next one change? what is added?

The answer is 6, because there is an increase of 6 for each term

Mars2501 [29]3 years ago

4 0

Answer:

common difference = 6.

Step-by-step explanation:

Given : 2, 8, 14, 20, 26, ......

To find : What is the common difference between successive terms in the sequence.

Solution : We have given that 2, 8, 14, 20, 26, ......

Common difference (d) = $a_{2} - a_{1}$ .

Where , $a_{2}$ . = any term other than first term

$a_{1}$ . = previous term.

Then common difference = 8 - 2 = 6.

14 - 8 = 6.

20 - 14 = 6.

Therefore, common difference = 6.

You might be interested in

Find the slope of the line passing through the points (-3,3) and (4,3)

garri49 [273]

Answer:

$slope = \frac{3 - 3}{4 - ( - 3)}$

$= 0$

8 0

3 years ago

The point (-2,3) is the solution to a system of two linear equations. Which of the following can be one of the

Fynjy0 [20]

Answer:

We conclude that The point (-2, 3) satisfies the equation y = -x+1.

Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.

Step-by-step explanation:

Given

The point (-2, 3)

<u>Checking option A</u>

Given the equation

y = 3x-2

substitute x = -2 and y = 3

3 = 3(-2) - 2

3 = -6 - 2

3 = -8

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y = 3x-2.

<u>Checking option B</u>

Given the equation

y = -x+1

substitute x = -2 and y = 3

3 = -(-2)+1

3 = 2+1

3 = 3

TRUE!

L.H.S = R.H.S

Thus,

The point (-2, 3) satisfies the equation y = -x+1.

<u>Checking option C</u>

Given the equation

y=x-1

substitute x = -2 and y = 3

3 = -2-1

3 = -3

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y=x-1.

<u>Checking option D</u>

Given the equation

y=2x+3

substitute x = -2 and y = 3

3 = 2(-2)+3

3 = -4+3

3 = -1

FALSE!

L.H.S ≠ R.H.S

Thus,

The point (-2, 3) does not satisfy the equation y=2x+3.

Conclusion:

Thus, we conclude that The point (-2, 3) satisfies the equation y = -x+1.

Hence, option B i.e. y = -x+1 is one of the equations of a system of two linear equations.

4 0

3 years ago

Please answer these you don’t need to show your work just answers please!!

boyakko [2]

#9- -1.42
#10- .04
#11- .232
#12- 6.6
#13- 4 505/1000
#14- -11/100
#15- 62/100
#16- -1 74/100

5 0

3 years ago

Could u help me with this

raketka [301]

Step-by-step explanation:

The vertex form of a parabola can be written as

$y = a(x - h)^2 + k$

where (h, k) are the coordinates of the parabola's vertex. So our parabola has the equation

$y = a(x + 7)^2 + 2$

Since the parabola passes through the point (-6, 4), we can solve for the constant a as follows:

$4 = a(-6 + 7)^2 + 2 \Rightarrow a = 2$

Therefore, the vertex form of the equation for the parabola is

$y = 2(x + 7)^2 +2$

8 0

3 years ago

Two curves are orthogonal if their tangent lines are perpendicular at each point of intersection. are the given families of curv

Akimi4 [234]

Hello,

$P(x,y)=x^2+y^2-ax=0\\\\
\dfrac{\partial{P}}{\partial{x}}=2x-a\\\\
\dfrac{\partial{P}}{\partial{y}}=2y\\\\


Q(x,y)=x^2+y^2-by=0\\\\
\dfrac{\partial{Q}}{\partial{x}}=2x\\\\
\dfrac{\partial{Q}}{\partial{y}}=2y-b\\\\

\dfrac{\partial{P}}{\partial{x}}*\dfrac{\partial{Q}}{\partial{x}}+\dfrac{\partial{P}}{\partial{y}}*\dfrac{\partial{Q}}{\partial{y}}=(2x-a)*2x+2y(2y-b)\\
=4x^2+4y^2-2ax-2by\\
=2(2x^2+2y^2-ax-by)\\
=2*P(x,y)+Q(x,y))\\
=2*(0+0)=0\\\\

Answer YES
$

5 0

3 years ago