Answer:
.0027 M
Explanation:
We must calculate the threshold concentration of PO3−4 using Ksp and the given concentration of Ca2+:
Ca3(PO4)2(s)⇌3Ca2+(aq)+2PO3−4(aq)
Ksp=8.6×10−19=[Ca2+]3[PO3−4]2=(4.9×10−5M)3[PO3−4]2
[PO3−4]=0.0027 M
Answer:
The molarity of the diluted HCl solution: <u>M₂ = 0.045 M</u>
Explanation:
To find- the molarity of the diluted HCl solution (M₂)
Given- <u>For original HCl solution</u>-
Molarity: M₁ = 1.5 M, Volume: V₁ = 60.0 ml = 0.06 L (∵ 1L = 1000 mL)
Then this original solution is diluted to a volume of 2 L
Thus <u>for the diluted HCl solution</u>-
The Volume of the diluted HCl solution: V₂ = 2 L
<u>So the Molarity of the diluted HCl solution (M₂) can be calculated by the </u><u><em>dilution equation:</em></u>
<u>Therefore, the molarity of the diluted HCl solution: M₂ = 0.045 M</u>
Answer:
<em>Various physical and chemical properties will be present in any matter.</em> For example, elements, molecules and compounds.
Physical properties can be described as the physical changes in which the composition of matter does not change place. For example, boiling point, melting point, appearance etc.
On the contrary, chemical properties can be described as the properties related to chemical changes. For example, burning of a wood into ash.