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Makovka662 [10]

3 years ago

13

Suppose you have a container filled with iron and sand. You can separate the iron from the sand if you ____________ so this is a

1 answer:

irinina [24]3 years ago

4 0

Answer:

Use a magnet; Mixture

Explanation:

Suppose you have a container filled with iron and sand. You can separate the iron from the sand if you use a magnet so this is a mixture.

A mixture is made up of two more components that are not chemically combined.
Mixtures may be classified as homogeneous when the components are in the same phase or heterogeneous when the components are in different phases.
A mixture of sand and iron is an example of solid-solid mixture which can be separated using a magnet.
The magnet will attract the iron in the mixture leaving the sand.

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When methanol, CH 3 OH , is burned in the presence of oxygen gas, O 2 , a large amount of heat energy is released. For this reas

luda_lava [24]

<u>Answer:</u> The mass of methanol that must be burned is 24.34 grams

<u>Explanation:</u>

We are given:

Amount of heat produced = 581 kJ

For the given chemical equation:

$CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l);\Delta H=-764kJ$

By Stoichiometry of the reaction:

When 764 kJ of heat is produced, the amount of methanol reacted is 1 mole

So, when 581 kJ of heat will be produced, the amount of methanol reacted will be = $\frac{1}{764}\times 581=0.7605mol$

To calculate mass for given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of methanol = 0.7605 moles

Molar mass of methanol = 32 g/mol

Putting values in above equation, we get:

$0.7605mol=\frac{\text{Mass of methanol}}{32g/mol}\\\\\text{Mass of methanol}=(0.7605mol\times 32g/mol)=24.34g$

Hence, the mass of methanol that must be burned is 24.34 grams

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