Answer:
What is the oxidation half reaction for iron?
The two elements involved, iron and chlorine, each change oxidation state; iron from +2 to +3, chlorine from 0 to -1. There are then effectively two half-reactions occurring. These changes can be represented in formulas by inserting appropriate electrons into each half-reaction: Fe2+ → Fe3+ + e.
Hope this helps..
Answer:
6,000kg/m3
Explanation:
6.00g/1cm3 x 1kg/1000g x 1cm3/0.000001m3
= 6.00kg/0.001m3
= 6,000kg/m3
The answer is C <span>The reactants lost internal energy.</span>
Answer:
4.25g
Explanation:
Molar concentration or molarity can be calculated thus;
Molarity (M) = number of moles (n) ÷ volume (V)
According to the provided information in this question, Volume = 5.0L, M = 0.050 M
number of moles = molarity × volume
n = 0.050 × 5
n = 0.25moles
Number of moles in a substance = mass (M) ÷ molar mass (MM)
Molar mass of ammonia (NH3) = 14 + 1(3)
= 17g/mol
Mass = moles × molar mass
Mass (g) = 0.25 × 17
Mass = 4.25g
