Answer:
The answer is C.
120 V with 60 W light bulb is 240 ohms.
120 V with 100 W light bulb is 144 ohms.
The 100 W bulb has less resistance :)
Explanation:
Below is an attachment containing the solution.
Answer:
Here the circuit in which a 4Ω resistor resistor is connected in series and two 8Ω resistor resistors are connected in parallel. Also, ammeter and voltmeter connected in series and parallel circuit respectively.
Now,
The maximum power of each resistance is 16 W
The 4Ω resistor is linked in series with the circuit.
so, P o w e r = I
two
R, here i is the current through the resistor resistor R
1 6 = I
two
∗ 4 Ω
i = 2A
Now 2A passes through parallel resistors of 8Ω resistance.
we know that, in parallel, the potential difference must be constant,
the current is divided into two parts, because the same resistance current in each resistance will be half. then the current through each resistor in parallel is
2 A
two
.
= 1 A
So finally the current through the 4Ω resistor = 2 A
current through each 8Ω resistor = 1 A
Explanation:
I hope this answer has helped you
Answer:
ω = 1.83 rad/s clockwise
Explanation:
We are given:
I1 = 3.0kg.m2
ω1 = -5.4rad/s (clockwise being negative)
I2 = 1.3kg.m2
ω2 = 6.4rad/s (counterclockwise being positive)
By conservation of the momentum:
I1 * ω1 + I2 * ω2 = (I1 + I2) * ω
Solving for ω:

Since it is negative, the direction is clockwise.
The density will be 1.05
The mass will be 13.65