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Fed [463]
2 years ago
7

The sum of three consecutive is -120. What are the three integers?

Mathematics
1 answer:
olga_2 [115]2 years ago
5 0

Answer:

-30 -40 -50

are the integers...

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Please show your work
Natasha_Volkova [10]

Answer:

X is equal to 4

5 0
2 years ago
The area of a square is 150 square inches. the length of its side is between which two values?
Sunny_sXe [5.5K]
A) Between 12 in and 13 in

6 0
3 years ago
the diagram shows a star made by surrounding a regular octagon with triangles, explain why angle a must be 135 degrees
horsena [70]

Answer:

From the sum of angles on a straight line, given that the rotation of each triangle attached to the sides of the octagon is 45° as they move round the perimeter of the octagon, the angle a which is supplementary to the angle turned by the triangles must be 135 degrees

Step-by-step explanation:

Given that the triangles are eight in number we have;

1)  (To simplify), we consider the five triangles on the left portion of the figure, starting from the bottom-most triangle which is inverted upside down

2) We note that to get to the topmost triangle which is upright , we count four triangles, which is four turns

3) Since the bottom-most triangle is upside down and the topmost triangle, we have made a turn of 180° to go from bottom to top

4) Therefore, the angle of each of the four turns we turned = 180°/4 = 45°

5) When we extend the side of the octagon that bounds the bottom-most triangle to the left to form a straight line, we see the 45° which is the angle formed between the base of the next triangle on the left and the straight line we drew

6) Knowing that the angles on a straight line sum to 180° we get interior angle in between the base of the next triangle on the left referred to above and the base of the bottom-most triangle as 180° - 45° = 135°.

6 0
3 years ago
Will give Brainliest! if right!
Leno4ka [110]
I believe it is B, but I'm still unsure !
7 0
3 years ago
A Mexican restaurant sells quesadillas in two sizes: a "large" 10 inch-round quesadilla and a "small" 5 inch-
elena-14-01-66 [18.8K]

Answer:

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

Step-by-step explanation:

we know that

The area of a circle is equal to

A=\pi r^2

where

r is the radius

step 1

Find the area of the 10 inch-round quesadilla

we have

D=10\ in

r=10/2=5\ in

substitute

A=\pi (5)^2

A=25\pi\ in^2

step 2

Find the area of the 5 inch-round quesadilla

we have

D=5\ in

r=5/2=2.5\ in

substitute

A=\pi (2.5)^2

A=6.25\pi\ in^2

step 3

Which is larger, half of the 10-inch quesadilla or the entire 5-inch quesadilla?

Compare

half of the 10-inch quesadilla is equal to ----> \frac{1}{2}(25\pi)=12.5\pi\ in^2

the entire 5-inch quesadilla ---->6.25\pi\ in^2

therefore

Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla

3 0
3 years ago
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