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Anna71 [15]
2 years ago
13

The potential energy of a body if its mass is 30 kg and height 30 m and gravity 10m/sec2​

Physics
1 answer:
Dafna1 [17]2 years ago
6 0

Explanation:

potential energy= mgh

30 × 10 × 30 = 9000J or 9KJ

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What are the characteristics of Parallel circuit??<br>​
NikAS [45]

Answer:

A parallel circuit has two or more paths for current to flow through.

Voltage is the same across each component of the parallel circuit.

The sum of the currents through each path is equal to the total current that flows from the source.

Explanation:

6 0
2 years ago
If a proton and an electron are released when they are 2.50×10^-10m apart (typical atomic distances), find the initial accelerat
katrin [286]

To solve this exercise, we will first proceed to calculate the electric force given by the charge between the proton and the electron (it). From the Force we will use Newton's second law that will allow us to find the acceleration of objects. The Coulomb force between two charges is given as

F = k \frac{q_1q_2}{r^2}

Here,

k = Coulomb's constant

q = Charge of proton and electron

r = Distance

Replacing we have that,

F = (9*10^9)(\frac{(1.602*10^{-19})^2}{2.5*10^{-10}})

F = 3.6956*10^{-9}N

The force between the electron and proton is calculated. From Newton's third law the force exerted by the electron on proton is same as the force exerted by the proton on electron.

The acceleration of the electron is given as

a_e = \frac{F}{m_e}

a_e = \frac{3.6956*10^{-9}}{9.11*10^{-31}}

a_e = 4.0566*10^{21}m/s^2

The acceleration of the proton is given as,

a_p = \frac{F}{m_p}

a_p = \frac{3.6956*10^{-9}}{1.672*10^{-27}}

a_p = 2.21*10^{18}m/s^2

3 0
2 years ago
A student connects a 1 hp motor to a bicycle. How much time will it take for the bicycle to accelerate from rest to a speed of 5
bija089 [108]

Answer:

t=2s

Explanation:

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P=\frac{W}{t}

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W=\Delta K

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\Delta K=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}=\frac{mv_f^2}{2}

And putting all together:

P=\frac{mv_f^2}{2t}

Since we want the time taken:

t=\frac{mv_f^2}{2P}

Which for our values is:

t=\frac{(120kg)(5m/s)^2}{2(746W)}=2s

7 0
3 years ago
Read 2 more answers
You pull a 70-kg crate at an angle of 30° above the horizontal. If you pull with a force of 600N and the coefficient of kinetic
Alenkinab [10]

Answer:

Explanation:

Force of friction acting on the body = μ mg cosθ

= .4  x 70 x 9.8 x cos30

= 237.63 N

component of weight = mgsinθ

= 70 x 9.8 x sin30

= 343 N  

Net upward force = 600 - mgsinθ - μ mg cosθ

= 600 - 343 - 237.63

= 105.37 N

acceleration in upward direction = 105.37 / 70

= 1.5 m /s²

s = ut + 1/2 a t²

= 0 + .5 x 1.5 x 3²

= 6.75 m .

5 0
3 years ago
If a football player has more mass they will also have more ______ ?<br> Fill in the blank
serg [7]

If a football player has more mass, they will also have more <u>momentum</u>. This is because mass is directly proportional to momentum.

3 0
3 years ago
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