-- Equations #2 and #6 are both the same equation,
and are both correct.
-- If you divide each side by 'wavelength', you get Equation #4,
which is also correct.
-- If you divide each side by 'frequency', you get Equation #3,
which is also correct.
With some work, you can rearrange this one and use it to calculate
frequency.
Summary:
-- Equations #2, #3, #4, and #6 are all correct statements,
and can be used to find frequency.
-- Equations #1 and #5 are incorrect statements.
Answer:
1.22gcm³
Explanation:
D = mass/ volume
Mass=1.840kg = 1,840g
1000g = 1kg
1.840kg= x(g)
X(g) = 1.840/1000
= 1840g
Volume = 0.0015m³= 1,500cm³
1m³= 1000,000cm³.
0.0015m³= x(cm³)
X(cm³) = 1000,000×0.0015
X(cm³)= 1500.
Since density is mass/volume, now impute your data's
D=m/v
D=1840/1500
1.22g/cm³
Answer: If mass remains constant and you double the force you will double the acceleration.
Answer:
Hearing range describes the range of frequencies that can be heard by humans or other animals, though it can also refer to the range of levels. The human range is commonly given as 20 to 20,000 Hz, although there is considerable variation between individuals, especially at high frequencies, and a gradual loss of sensitivity to higher frequencies with age is considered normal. Sensitivity also varies with frequency, as shown by equal-loudness contours. Routine investigation for hearing loss usually involves an audiogram which shows threshold levels relative to a normal.
Several animal species are able to hear frequencies well beyond the human hearing range. Some dolphins and bats, for example, can hear frequencies up to 100,000 Hz. Elephants can hear sounds at 14–16 Hz, while some whales can hear infrasonic sounds as low as 7 Hz (in water).
Explanation:
HOPE THIS HELPS!!!
