The downwards component of weight of the object would be 35sin25 degrees = 14.8
F=14.8 - 8 = 6.8 N m= 35/9.8= 3.57 kg
F=mA
Therefore,
3.57A= 6.8 N
=> A= 6.8/3.57
=> A= 1.902 ms^-2
F(max)= (U)R where (U)= coefficient of friction
and R= Normal reaction force
R= 35cos25
= 31.72 N
Since, F(max)= 8
8= (U)* 31.72
=>(U)= 8/31.72
=>(U)= 0.25
they have zero momentum before pushing off, is at least true
Answer:
C
Explanation:
During an investigation you want to investigate different variables.
It's not so much a "contradiction" as an approximation. Newton's law of gravitation is an inverse square law whose range is large. It keeps people on the ground, and it keeps satellites in orbit and that's some thousands of km. The force on someone on the ground - their weight - is probably a lot larger than the centripetal force keeping a satellite in orbit (though I've not actually done a calculation to totally verify this). The distance a falling body - a coin, say - travels is very small, and over such a small distance gravity is assumed/approximated to be constant.
