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nexus9112 [7]
4 years ago
7

Properties of water what makes water so special

Chemistry
1 answer:
sertanlavr [38]4 years ago
7 0
•boiling and freezing point
•surface tension
•vapor pressure
• solid state
•liquid state
•gaseous state
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2 Which two substances cause iron to rust?
guapka [62]

Answer:

water and oxygen

Explanation:

this is because

iron + water + oxygen ----> hydrated iron (III) oxide (which is rust in lame terms )

hope this helps

please mark it brainliest

8 0
3 years ago
Which best explains why a crystal is incompressible?
Finger [1]
I think the correct answer from the choices listed above is option C. The statement that best explains why a crystal is incompressible would be that there is little, if any, space left between its adjacent molecules. Hope this answers the question. Have a nice day.
5 0
3 years ago
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What challenges do scientists face in studying the Sun?
svet-max [94.6K]
The Radiations maybe and not being burned alive
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3 years ago
What is thermal boundary layers
bagirrra123 [75]

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the layer of a liquid or gaseous heat-transfer agent between the free stream and a heat-exchange surface. In this layer the temperature of the heat-transfer agent changes from that of the wall to that of the free stream

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8 0
4 years ago
What is the change in internal energy for each of the following situations? 1. q-7.9 J out of the system and w 3.6 J done on the
adoni [48]

Answer:

A i. Internal energy ΔU = -4.3 J ii. Internal energy ΔU = -6.0 J B. The second system is lower in energy.

Explanation:

A. We know that the internal energy,ΔU = q + w where q = quantity of heat and w = work done on system.

1. In the above q = -7.9 J (the negative indicating heat loss by the system). w = 3.6 J (It is positive because work is done on the system). So, the internal energy for this system is ΔU₁ = q + w = -7.9J + 3.6J = -4.3 J

ii. From the question q = +1.5 J (the positive indicating heat into the system). w = -7.5 J (It is negative because work is done by the system). So, the internal energy for this system is ΔU₂ = q + w = +1.5J + (-7.5J) = +1.5J - 7.5J = - 6.0J

B. We know that ΔU = U₂ - U₁ where U₁ and U₂ are the initial and final internal energies of the system. Since for the systems above, the initial internal energies U₁ are the same, then we say U₁ = U. Let U₁ and U₂ now represent the final energies of both systems in A i and A ii above. So, we write ΔU₁ = U₁ - U and ΔU₂ = U₂ - U where ΔU₁ and ΔU₂ are the internal energy changes in A i and A ii respectively. Now from ΔU₁ = U₁ - U, U₁ = ΔU₁ + U and U₂ = ΔU₂ + U. Subtracting both equations U₁ - U₂ = ΔU₁ - ΔU₂

= -4.3J -(-6.0 J)= 1.7 J. Since U₁ - U₂ > 0 , U₂ < U₁ , so the second system's internal energy increase less and is lower in energy and is more stable.

8 0
3 years ago
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