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astra-53 [7]
2 years ago
15

Answerr please :))))

Mathematics
2 answers:
jeyben [28]2 years ago
8 0

Answer:

20

Step-by-step explanation:

substitute 5 for 'x':

6(5) - 2(5) = 30-10 = 20

Crazy boy [7]2 years ago
5 0
6x-2x
6(5)-2(5)
30 - 10 = 20
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Determine the slope of the following graph.
evablogger [386]

Answer:

2/1 or 2

Step-by-step explanation:

if you find a spot were the line is line up with the boxes in the graph like at (-2,0) up 2 and right one you will see the line is lined up again and since slope is rise/run its 2/1 or 2

4 0
3 years ago
Angle JKL is an equilateral triangle jk=13x+5 KL=17x-19 and JL=8x+35
Goshia [24]

The value of x is 6, then the value of JK is 83, KL is 83 and JL is 83.

<h3>What is a triangle?</h3>

A triangle is a polygon that has three sides and three vertices. It is one of the basic figures in geometry.

An equilateral triangle is a shape with three sides that have an equal measure of side length.

The 3 sides of triangle JKL are equal to each other, therefore we can equate any of the two sides together to find the unknown variable called x.

So, JK = KL

JK = 13x + 5

KL + 17x - 19

13x + 5 = 17x - 19

Collect like terms;

17x - 13x = 19 + 5

4x = 24

x = 24/4

x = 6

We can now proceed to find the sides;

JK = 13x + 5

13 x 6 + 5

= 78 + 5

= 83

JK = 83

KL = 17x - 19

= 17 x 6 - 19

= 102 - 19

= 83

KL = 83

JL= 8x + 35​

= 8 x 6 + 35

= 48 + 35

= 83

JL = 83

Hence, The value of x is 6, then the value of JK is 83, KL is 83 and JL is 83.

Learn more about the triangles;

brainly.com/question/2773823

#SPJ1

7 0
2 years ago
8) through: (-3, -2), perp. to y = x – 1<br> A) y=-5x – 1 B) y=-4x – 5<br> C) y=-x – 5 D) y=-5x – 4
nexus9112 [7]

<u>Answer:</u>

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

<u>Solution:</u>

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1

We know that, <em>product of slopes of perpendicular lines is -1. </em>

So, 1 \times slope of perpendicular line =  -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0
4 years ago
Can someone help me out :P
GuDViN [60]

Answer:

ummmm im sorry but i need points uwu love you<3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve for the variable: -4h + 2 = 18 <br> A. -4<br> B. -2<br> C. 1<br> D. 6
Anna [14]
You need to isolate the variable <em>h</em>. 

1) Subtract both sides by 2. 

-4h + 2 = 18
-4h + 2 - 2 = 18 - 2
-4h = 16

2) Divide both sides by -4 (the coefficient). 
(-4h) / -4 = 16 / -4
h = -4 
5 0
3 years ago
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