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gavmur [86]
2 years ago
7

What is the formula for the compound formed when a potassium ion (K ) and a sulfide ion (S2-) unite?.

Chemistry
1 answer:
cupoosta [38]2 years ago
6 0

Answer:

The chemical formula for potassium sulfide is K2 S. Sulfur atoms need two electrons to fill their 3p electron orbitals.

Explanation:

You might be interested in
True or false? different reactions require different catalysts.
lapo4ka [179]

True, different reactions require different catalysts. Hence, option 1 is correct.

<h3>What are catalysts?</h3>

A catalyst is a substance that speeds up a chemical reaction or lowers the temperature or pressure needed to start one, without itself being consumed during the reaction.

Though a catalyst is supposed to remain unaltered at the end of the reaction, it does take part in the reaction by providing active centres for the reaction to take place.

By helping to form a suitable activated complex in the course of the reaction, the catalyst increases the rate of formation of the product, as well as its yield.

Therefore, a catalyst has to be reactant-specific to form the favourable activated complex or intermediate.

Hence, option 1 is correct.

Learn more about the catalysts here:

brainly.com/question/12260131

#SPJ1

8 0
1 year ago
Gaseous butane, CH3(CH2)2CH, reacts with gaseous oxygen gas, O2, to produce gaseous carbon dioxide, CO2, and gaseous water, H2O.
weeeeeb [17]

Answer:

Percentage yield of carbon dioxide is 49.9%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3(CH2)2CH3 + 13O2 —> 8CO2 + 10H2O

OR

2C4H10 + 13O2 —> 8CO2 + 10H2O

Next, we shall determine the masses of butane and oxygen that reacted and the mass of carbon dioxide produced from the balanced equation. This is illustrated below:

Molar mass of butane C4H10 = (12×4) + (10×1)

= 48 + 10

= 58 g/mol

Mass of C4H10 from the balanced equation = 2 × 58 = 116 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 13 × 32 = 416 g

Molar mass of CO2 = 12 + (16×2)

= 12 + 32

= 44 g/mol

Mass of CO2 from the balanced equation = 8 × 44 = 352 g

Summary:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen to produce 352 g of carbon dioxide.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

116 g of butane reacted with 416 g of oxygen.

Therefore, 34.29 g of butane will react with = (34.29 × 416) / 116 = 122.97 g of oxygen.

From the calculation made above, we can see clearly that only 122.97 g out of 165.7 g of oxygen reacted completely with 34.29 g of butane. Therefore, butane is the limiting reactant and oxygen is the excess reactant.

Next, we shall determine the theoretical yield of carbon dioxide.

In this case, we shall use the limiting reactant because it will give the maximum yield of carbon dioxide as all of it is used up in the reaction.

The limiting reactant is butane and the theoretical yield of carbon dioxide can be obtained as follow:

From the balanced equation above,

116 g of butane reacted to produce 352 g of carbon dioxide.

Therefore, 34.29 g of butane will react to produce = (34.29 × 352) / 116 = 104.05 g of carbon dioxide.

Therefore, the theoretical yield of carbon dioxide is 104.05 g

Finally, we shall determine the percentage yield of carbon dioxide as follow:

Actual yield of carbon dioxide = 51.9 g

Theoretical yield of carbon dioxide = 104.05 g

Percentage yield of carbon dioxide =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield of carbon dioxide = 51.9 / 104.05 × 100

Percentage yield of carbon dioxide = 49.9%

7 0
3 years ago
What is the main idea of the kinetic theory of heat?
Goshia [24]
 – liquids, solids or gases – are made up of atoms and molecules that are in constant motion.<span> The theory also states that collisions between atoms and molecules are elastic</span>
5 0
3 years ago
How many grams of lithium hypochlorite (LiClO) are there in 0.594 moles?
Flauer [41]

Answer : The mass of lithium hypochlorite are, 34.7 grams.

Explanation : Given,

Moles of LiClO = 0.594 g

Molar mass of LiClO = 58.4 g/mol

Expression used :

\text{ Mass of }LiClO=\text{ Moles of }LiClO\times \text{ Molar mass of }LiClO

Now put all the given values in this expression, we get:

\text{ Mass of }LiClO=(0.594moles)\times (58.4g/mole)

\text{ Mass of }LiClO=34.7g

Therefore, the mass of lithium hypochlorite are, 34.7 grams.

3 0
3 years ago
How many moles of NaCl must be dissolved in 0.5 L of water to make a 4 mole/L
kvv77 [185]
C = 4 mol/l
v = 0.5 l

n(NaCl)=cv

n(NaCl) = 4 mol/l · 0.5 l = 2 mol

2 moles of NaCl must be dissolved

5 0
3 years ago
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