Answer:
179 L of CO2
Explanation:
Given the equation of the reaction;
C2H6(g) + 7/2 O2(g) -------> 2CO2(g) + 3H2O(g)
Now 1 mole of ethane yields 2 moles of CO2 from the balanced reaction equation
1 mole of a gas occupies 22.4 L volume so,
22.4 L of ethane yields 44.8 L of CO2
89.5 L of ethane yields 89.5 * 44.8/22.4 = 179 L of CO2
Answer:
The new mass/volume percent is 2.0% (m/v)
Explanation:
Dilution is a procedure by which the concentration of a solution is decreased, generally with the addition of a diluent. In other words, dilution is a process in which a concentrated solution is always started, to which a greater volume of solvent is added, causing the concentration and volume of the resulting solution to change. But the amount of solute used to prepare the initial solution remains the same.
The calculation of a dilution is made by:
Cinitial. Vinitial = Cfinal. Vfinal
where C indicates concentration and V indicates volume.
In this case:
- Cinitial: 6.0% (m/v)
- Vinitial: 110 mL
- Cfinal: ?
- Vfinal: 330 mL
Replacing:
6.0% (m/v) * 110 mL= Cfinal* 330 mL
Solving:

Cfinal= 2.0% (m/v)
<u><em>The new mass/volume percent is 2.0% (m/v)</em></u>
27.9L
Explanation:
Given parameters:
Number of molecules = 7.5 x 10²⁴molecules
Condition = STP
Unknown:
Volume of gas = ?
Solution;
The volume of gas at STP is expressed below;
Volume of gas = number of moles x 22.4
Number of moles = 
Now if we can obtain the value of the number of moles from the expression above, we can plug it back into the equation of the volume of gas at STP;
Number of moles of NH₃ =
}{6.02 x 10^{23} }[/tex]
Number of moles of NH₃ = 12.5moles
Volume of gas = 12.5 x 22.4 = 27.9L
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Volume of gas at STP brainly.com/question/7795301
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Answer: I think the answer might be yes..
Explanation:
Answer: 125 g
Explanation:
To calculate the moles :

The balanced reaction is:
According to stoichiometry :
1 mole of
require = 3 moles of 
Thus 1.30 moles of
will require=
of 
Mass of 
Thus 125 g of
will be needed to burn 36.1 g of 