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Georgia [21]
3 years ago
6

What is the effect of decreasing concentration of sodium hydroxide ten times in standardization​

Chemistry
1 answer:
tatuchka [14]3 years ago
7 0

Answer:

[Translation] pH will decrease by 1.

Explanation:

See attached image. The translation is in the "Answer".

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How many liters of carbon dioxide will be produced when 89.5 L of ethane are burned? (One mole of any gas occupies 22.4 L under
yan [13]

Answer:

179 L of CO2

Explanation:

Given the equation of the reaction;

C2H6(g) + 7/2 O2(g) -------> 2CO2(g) + 3H2O(g)

Now 1 mole of ethane yields 2 moles of CO2 from the balanced reaction equation

1 mole of a gas occupies 22.4 L volume so,

22.4 L of ethane yields 44.8 L of CO2

89.5 L of ethane yields 89.5 * 44.8/22.4 = 179 L of CO2

4 0
3 years ago
What is the new mass/volume percent (m/v) of a KOH solution that is prepared by diluting 110 mL of a 6.0% (m/v) KOH solution to
denis-greek [22]

Answer:

The new mass/volume percent is 2.0% (m/v)

Explanation:

Dilution is a procedure by which the concentration of a solution is decreased, generally with the addition of a diluent. In other words, dilution is a process in which a concentrated solution is always started, to which a greater volume of solvent is added, causing the concentration and volume of the resulting solution to change. But the amount of solute used to prepare the initial solution remains the same.

The calculation of a dilution is made by:

Cinitial. Vinitial = Cfinal. Vfinal

where C indicates concentration and V indicates volume.

In this case:

  • Cinitial: 6.0% (m/v)
  • Vinitial: 110 mL
  • Cfinal: ?
  • Vfinal: 330 mL

Replacing:

6.0% (m/v) * 110 mL= Cfinal* 330 mL

Solving:

Cfinal=\frac{ 6.0 (m/v)*110 mL}{330 mL}

Cfinal=   2.0% (m/v)

<u><em>The new mass/volume percent is 2.0% (m/v)</em></u>

4 0
3 years ago
What is the volume of 7.50 x 10^24 molecules of NH3 at STP?
Allushta [10]

27.9L

Explanation:

Given parameters:

Number of molecules = 7.5 x 10²⁴molecules

Condition = STP

Unknown:

Volume of gas = ?

Solution;

The volume of gas at STP is expressed below;

 Volume of gas = number of moles x 22.4

Number of moles = \frac{Number of molecules }{6.02 x 10^{23} }

    Now if we can obtain the value of the number of moles from the expression above, we can plug it back into the equation of the volume of gas at STP;

     Number of moles of NH₃ =  \frac{[tex]7.5 x 10^{24} }{6.02 x 10^{23} }[/tex]

   Number of moles of NH₃ = 12.5moles

Volume of gas = 12.5 x 22.4 = 27.9L

learn more:

Volume of gas at STP brainly.com/question/7795301

#learnwithBrainly

3 0
3 years ago
HBr + H2SO4 = SO2 + Br2 + H2O<br> Did S change oxidation number?
galben [10]

Answer: I think the answer might be yes..

Explanation:

7 0
3 years ago
Read 2 more answers
From the unbalanced reaction: B2H6 + O2 ---&gt; HBO2 + H2O
Drupady [299]

Answer: 125 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} B_2H_6=\frac{36.1g}{17}=1.30moles

The balanced reaction is:

B_2H_6+3O_2\rightarrow 2HBO_2+2H_2O

According to stoichiometry :

1 mole of B_2H_6 require = 3 moles of O_2

Thus 1.30 moles of B_2H_6 will require=\frac{3}{1}\times 1.30=3.90moles  of O_2

Mass of O_2=moles\times {\text {Molar mass}}=3.90moles\times 32g/mol=125g

Thus 125 g of O_2 will be needed to burn 36.1 g of B_2H_6

4 0
3 years ago
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