Ask question

Ask question

All categories

3 years ago

13

One degree Celsius indicates the same temperature change as?

1 answer:

VARVARA [1.3K]3 years ago

6 0

If you've ever seen the formula from Celsius to Fahrenheit...

$C=\frac59(F-32)$

As you can see, if you put in some number of Celsuis C your answer is going to be multiplied by 5/9...meaning that 1°C = 5/9°F.

As for Kelvin, it's literally just Celsuis, but about 273.15° more.

B. 5/9°F

You might be interested in

Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.650 µC charge and flies due west at a speed of

Ganezh [65]

Answer : $F=2808\times 10^{-11}\ N$

Explanation :

It is given that,

Charge, $q=0.650\ \mu C=0.65\times 10^{-6}\ C$

Velocity of Aircraft, $v=540\ m/s$ (in west)

Magnetic field, $B=8 \times 10^{-5}\ T$ ( in north )

Using the relation as :

$F=q(v\times B)$

Magnetic force is ,

$F=0.65\times 10^{-6}\ C\times 540\ m/s\times 8 \times 10^{-5}\ T$

$F=2808\times 10^{-11}\ N$

Using Right hand thumb rule, the direction of force is in the plane perpendicular to the velocity and the magnetic field i.e. $-\hat{k}$ .

4 0

4 years ago

A rotating water pump works by taking water in at one side of a rotating wheel, and expelling it from the other side. If a pump

Xelga [282]

Answer:

Explanation:

initial angular velocity, ωo = 0 rad/s

angular acceleration, α = 30.5 rad/s²

time, t = 9 s

radius, r = 0.120 m

let the velocity is v after time 9 s.

Use first equation of motion for rotational motion

ω = ωo + αt

ω = 0 + 30.5 x 9

ω = 274.5 rad/s

v = rω

v = 0.120 x 274.5

v = 32.94 m/s

8 0

3 years ago

I NEED HELP ASAP

Levart [38]

Answer:

ig d. transmits only green light.....

8 0

1 year ago

Electromagnetic wav

krek1111 [17]

Answer:

I dont get what your asking sorry boo

Explanation:

6 0

3 years ago

Read 2 more answers

A mass of 3.6 kg oscillate on a horizontal spring with a spring constant of 160 N/m.

Darya [45]

Answer:

48.7 J

Explanation:

For a mass-spring system, there is a continuous conversion of energy between elastic potential energy and kinetic energy.

In particular:

- The elastic potential energy is maximum when the system is at its maximum displacement

- The kinetic energy is maximum when the system passes through the equilibrium position

Therefore, the maximum kinetic energy of the system is given by:

$KE=\frac{1}{2}mv^2$

where

m is the mass

v is the speed at equilibrium position

In this problem:

m = 3.6 kg

v = 5.2 m/s

Therefore, the maximum kinetic energy is:

$KE=\frac{1}{2}(3.6)(5.2)^2=48.7 J$

6 0

3 years ago