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3 years ago

One degree Celsius indicates the same temperature change as?

1 answer:

6 0

If you've ever seen the formula from Celsius to Fahrenheit...

$C=\frac59(F-32)$

As you can see, if you put in some number of Celsuis C your answer is going to be multiplied by 5/9...meaning that 1°C = 5/9°F.

As for Kelvin, it's literally just Celsuis, but about 273.15° more.

B. 5/9°F

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Two blocks can collide in a one-dimensional collision. The block on the left hass a mass of 0.40 kg and is initially moving to t

Dmitrij [34]

Answer:

The velocity of the first block is 1.15m/s while of the second block 2.56m/s.

Explanation:

Momentum is only conserved in an isolated system, and because this problem requires us to find the value of the two variables, we need two equations; therefore, to conserved momentum the energy must be released in to the system only after the collision has occurred.

Therefore, from conservation of momentum

$m_1v_1= m_1v_{1f}+m_2v_{2f}$

$0.4(2.4)= 0.4v_{1f}+0.5v_{2f}$

$\boxed{\:0.96= 0.4v_{1f}+0.5v_{2f}}$

and from conservation of energy

$\frac{1}{2}m_1v_1^2+1.2 = \frac{1}{2} m_1v_{1f}^2+\frac{1}{2}m_2v_{2f}^2$

$m_1v_1^2+2.4 = m_1v_{1f}^2+m_2v_{2f}^2}$

$\boxed{\:3.804= 0.4v_{1f}^2+0.5v_{2f}^2.}$

Thus, we have two equations and two unknowns

$(1). \: 0.4v_{1f}+0.5v_{2f}=0.96$

${(2). \: 0.4v_{1f}^2+0.5v_{2f}^2 =3.804$

which has solutions

$(v_{1f}, v_{2f}) = (1.15,2.56)$

and

$(v_{1f}, v_{2f}) = (1.15,-2.56)$

Since the blocks cannot pass through each other, the 0.5kg block cannot have $v_{2f} = -2.56m/s$ (moves to the left) while the 0.4 kg block has $v_{1f} = 1.15m/s$ (moves to the right); therefore, we take the first solution for the velocities:

$(v_{1f}, v_{2f}) = (1.15,2.56)$ .

Thus , the velocity of the first block is 1.15m/s while of the second block 2.56m/s.

5 0

3 years ago

Read 2 more answers

The maximum energy a bone can absorb without breaking is surprisingly small. Experimental data show that both leg bones, togethe

wolverine [178]

Answer:

0.21m

Explanation:

Note that the 200 J before breaking legs is Kinetic energy

So if potential energy= kinetic energy

Then 200J = mgh

h= 200/75x 9.8

= 0.21m so the maximum height will be 0.21m

5 0

3 years ago

"A 0.4 kg mass, attached to the end of a 0.75 m string, is whirled around in a circular horizontal path. If the maximum tension

Nimfa-mama [501]

Answer:

The maximum velocity the mass can have if the string is not to break = 29.05 m/s

Explanation:

The force balance in the mass:

The tension in the string must always be equal to the force keeping the mass in horizontal circular motion.

The force keeping the mass in circular motion is given by

F = mv²/r

m = mass of body = 0.4 kg

v = speed of the body in circular motion

r = radius of the circular motion = 0.75 m

Maximum tension the string can withstand will correspond to the maximum velocity of the body in horizontal circular motion

T = F = mv²/r

450 = (0.4)(v²)/(0.75)

v² = 450×0.75/0.4 = 843.75

v = 29.05 m/s

4 0

3 years ago

Read 2 more answers

2. A rock is dropped off a bridge. How fast is the rock

zhenek [66]

Answer:

a) The velocity of rock at 1 second, v = 9.8 m/s

b) The velocity of rock at 3 second, v = 29.4 m/s

c) The velocity of rock at 5.5 second, v = 53.9 m/s

Explanation:

Given data,

The rock is dropped from a bridge.

The initial velocity of the rock, u = 0

a) The velocity of rock at 1 second,

Using the first equation of motion

v = u + gt

v = 0 + 9.8 x 1

v = 9.8 m/s

b) The velocity of rock at 3 second,

v = u + gt

v = 0 + 9.8 x 3

v = 29.4 m/s

c) The velocity of rock at 5.5 second,

v = u + gt

v = 0 + 9.8 x 5.5

v = 53.9 m/s

5 0

3 years ago

PLEASE HELP!!!! Thank you!

V125BC [204]

it would be a chain reaction and a wave

6 0

3 years ago