The hyppo is standing completely submerged on the bottom of the lake. Since it is still, it means that the net force acting on it is zero: so, the weight of the hyppo (W), pushing downward, is balanced by the upward normal force, N:

$W-N=0$ (1)

the weight of the hyppo is

$W=mg=(1500 kg)(9.8 m/s^2)=14,700 N$

where m is the hyppo's mass and g is the gravitational acceleration; therefore, solving eq.(1) for N, we find

$N=W=14,700 N$

8 0

3 years ago

A car has a mass off 2,00 kg & is traveling at 28 meters per second. what is the car’s kinetic energy?

Sunny_sXe [5.5K]

Answer:

kelechi(- Osinbajo b.d al henkel

5 0

3 years ago

PHYSICS<br> I need help with number two!!!!

EleoNora [17]

Answer:

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

Explanation:

Initial total energy = final total energy

PE₁ + KE₁ = PE₂ + KE₂

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

7 0

3 years ago

What is the net force needed to accelerate a 21.4 kg grocery sack upward at 1.5 m/s2?

marshall27 [118]

Answer:

32.1 N Please Give Brainliest

Explanation:

force = mass x acceleration

8 0

2 years ago