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3 years ago

PLEASE HELP ME!!!!!!!!!!

Physics

1 answer:

Gekata [30.6K]3 years ago

8 0

B, John Dalton. He thought that the atom was the smallest particle in the universe

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Suppose a square wave signal has a 65 percent duty cycle and an on-state voltage of 40 volts DC. What is the average DC voltage

Ierofanga [76]

Answer:

The voltage is $\= DC _v = 2.6 \ V$

Explanation:

From the question we are told that

The duty cycle is p = 65% = 0.65

The on - state voltage is $V = 40 \ volt$

Generally the average DC voltage is mathematically represented as

$\= DC _v = p * V$

=> $\= DC _v = 40 * 0.65$

=> $\= DC _v = 2.6 \ V$

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2 years ago

A perfect bouncy ball would continue bouncing the same height forever. But in reality, the ball stops bouncing because energy is

galina1969 [7]

Answer:

D. all answers are true

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3 years ago

Which of these determines an objects ability to sink or float in water?

Zigmanuir [339]

Answer:

C. Density

Explanation:

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2 years ago

A balloon is expanded to the same volume as that of a human head. Do an order-of-magnitude estimate of the volume of this balloo

cestrela7 [59]

Answer:

Volume of balloon = 1000 cm^3

Explanation:

The head of a normal person can be assumed as a sphere with radius 10 cm.

Volume of sphere $=\frac{4}{3} \pi r^3$ , where r is the radius.

We have approximate radius = 10 cm.

Approximate volume of head $=\frac{4}{3} \pi r^3=\frac{4}{3} *\pi* 10^3=4188cm^3$

In the given options the closest value to the approximate volume is 1000 cm^3.

So, volume of head = Volume of balloon = 1000 cm^3

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2 years ago

It may seem strange that the selected velocity does not depend on either the mass or the charge of the particle. (For example, w

Charra [1.4K]

Answer:

b) q large and m small

Explanation:

q is large and m is small

We'll express it as :

q > m

As we know the formula:

F = Eq

And we also know that :

F = Bqv

F = $\frac{mv^{2} }{r}$

Bqv = $\frac{mv^{2} }{r}$

or Eq = $\frac{mv^{2} }{r}$

Assume that you want a velocity selector that will allow particles of velocity v⃗ to pass straight through without deflection while also providing the best possible velocity resolution. You set the electric and magnetic fields to select the velocity v⃗ . To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) you would want to use particles with q large and m small.

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3 years ago