PLEASE HELP!!!! Thank you!

What is the maximum and minimum wavelength of echolocation?

nadezda [96]

I believe the answer is 40,000 Hz to 100,000 Hz

7 0

3 years ago

Sound waves travel in air at 343 m/s. The lowest frequency one can hear is 25.0 Hz; the highest frequency is 25.0 kHz. Find the

Slav-nsk [51]

Answer:

13.72 m and 0.01372 m respectively

Explanation:

Wavelength: This can be defined as the distance covered in one complete oscillation. The S.I unit of wavelength is meter (m).

The formula for the speed of a wave is given as

v = λf ............................. Equation 1

Where v = speed of the sound wave, λ = wavelength, f = frequency of the sound wave.

make λ the subject of the equation,

λ = v/f ......................... Equation 2

For the lowest frequency,

Given: f = 25 Hz, v = 343 m/s.

Substitute into equation 2

λ = 343/25

λ = 13.72 m.

For the highest frequency,

Given: f = 25 kHz = 25000 Hz, v = 343 m/s

Substitute into equation 2

λ = 343/25000

λ = 0.01372 m.

The wavelength of sound for 25 Hz and 25 kHz = 13.72 m and 0.01372 m respectively

8 0

3 years ago

The primary purpose of a mirror is to _________ light rays.

Effectus [21]

a. reflect (I found this using prior knowledge and process of illumination it can't be absorb cuz you wouldn't see anything it can't be refract because it doesn't reverse the image and it isn't transmit )

8 0

3 years ago

A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the centripetal

Lynna [10]

Wow ! This will take more than one step, and we'll need to be careful
not to trip over our shoe laces while we're stepping through the problem.

The centripetal acceleration of any object moving in a circle is

      (speed-squared) / (radius of the circle) .

Notice that we won't need to use the mass of the train.

We know the radius of the track. We don't know the trains speed yet,
but we do have enough information to figure it out. That's what we
need to do first.

Speed = (distance traveled) / (time to travel the distance).

Distance = 10 laps of the track.   Well how far is that ? ? ?

1 lap = circumference of the track = (2π) x (radius) = 2.4π meters

10 laps = 24π meters.

Time = 1 minute 20 seconds = 80 seconds

The trains speed is (distance) / (time)

   = (24π meters) / (80 seconds)

   = 0.3 π meters/second .

NOW ... finally, we're ready to find the centripetal acceleration.

<span> (speed)² / (radius)

   = (0.3π m/s)² / (1.2 meters)

   = (0.09π m²/s²) / (1.2 meters)

   =    (0.09π / 1.2) m/s²

   =    0.236 m/s² . (rounded)

If there's another part of the problem that wants you to find
the centripetal FORCE ...

Well, Force = (mass) · (acceleration) .

We know the mass, and we ( I ) just figured out the acceleration,
so you'll have no trouble calculating the centripetal force. </span>

4 0

3 years ago

Monochromatic light of wavelength λ=136.8μ m is shone at normal incidence through a thin film of thickness t resting atop a full

inn [45]

Answer:

1.8 × 10⁻⁸ Hm

Explanation:

Given that:

The refractive index of the film = 19

The wavelength of the light = 136.8 μ m

The thickness can be calculated by using the formula shown below as:

$Thickness=\frac {\lambda}{4\times n}$

Where, n is the refractive index of the film

${\lambda}$ is the wavelength

So, thickness is:

$Thickness=\frac {136.8\ \mu\ m}{4\times 19}$

Thickness = 1.8 μ m

Since,

1 μ m = 10⁻⁸ Hm

So,

Thickness = 1.8 × 10⁻⁸ Hm

7 0

3 years ago