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kupik [55]
2 years ago
14

how do you find work when only given the angle a sled is pulled, the mass, the coefficent of kinetic friction and distance

Physics
1 answer:
Sergio039 [100]2 years ago
8 0

Answer:

W = F * s    

Work done equals applied force * distance traveled

Apparent weight = M g (1 - sin θ)     since some of applied force will lighten sled

μ = coefficient of kinetic friction

F cos θ = force applied to motion of sled

s = distance traveled

[μ M g (1 - sin θ)] cos θ * s = work done in moving sled

Note that F = μ M g    if applied force is in the horizontal direction

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Why does it take the water in a swimming pool some time to heat up during a hot day?
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5 0
3 years ago
The electric force between two charged balloons is 0.12 newtons. If the distance between the two balloons is halved, what will b
marshall27 [118]

Answer:

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Explanation:

5 0
3 years ago
(a) An object that has a small mass and an object that has a large mass have the same momentum. Which object has the largest kin
Iteru [2.4K]

Answer:

A) The smaller object; B) The larger object

Explanation:

A) Lets say the small object is 2 kg and the large one is 6 kg. Lets say they also have 30 kg*m/s of momentum each. The small object would have 15 m/s velocity and the large would have 5 m/s.

Now for kinetic energy(.5*m*v²), the small object is .5*2*15², which is 225 J

The large object is .5*6*5², which is 75 J, so the smaller object has more Kinetic energy. Since velocity is squared, it is more important than how large mass is.

B) Same masses as part A. Lets say the kinetic energy is 45 J for both of them. For the small object, 45=.5*2*v²

.5*2 is 1, so 45/1 is 45. Take the square root and we get v= 6.71 m/s

For the large object, 45=.5*6*v²

.5*6 is 3, so 45/3 is 15. Take the square root and we get v=3.87 m/s

Now we plug the velocities into p=mv

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For the large object, p=6*3.87, which gives us p=23.22 kg*m/s

The larger object has the larger momentum.

Hope this helps

5 0
3 years ago
How long it takes to reach maximum height in seconds
olganol [36]
The dotted path is the path of the ball. it reaches it's maximum height at the top where vertical, y-velocity = 0
The initial y-velocity = 19sin(70°)
initial y-velocity = 17.85 m/s

Use one of the kinematic equations with velocity and time. No displacement because we don't want to worry about figuring that out.

v = u - gt
0 = 17.85 - 9.8t
-17.85 = -9.8t
17.85/9.8 = t
1.82 sec = t




6 0
3 years ago
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