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Bess [88]
3 years ago
6

Difine scalar quantity​

Physics
1 answer:
vfiekz [6]3 years ago
8 0

Scalar quantity are physical quantities that have just magnitude, not direction.

  • It is always positive.
  • Examples: Speed, distance
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Animals, including humans, need shelter, food, water, air, and space in order to survive. How do animals satisfy their basic nee
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<span>Every organism has its own way of making sure its basic needs are met.</span>
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3 years ago
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Three moles of an ideal gas are taken around the eyele acb shown in Fig.For this gas Co-29.2J/mol-K.Process ac is at constant pr
Scorpion4ik [409]

For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as

Wt=1945.475J

<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>

Generally, the equation for work  is mathematically given as

Wt=wac+Wc+Wba

Therefore

Wac=Pa(Vc-Va)=nR(Tc-Ta)

Wac=3(8.314*192)

Wac=4788.864J

Wcb=P1v1-p2v2/v-1

Wcb-3*8.34*108/0.4

Wcb=-6734.34J

Wab=0

In conclusion,

Wt=wac+Wc+Wba

Wt=4788.864J+0+(-6734.34J)

Wt=+1945.475J

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8 0
2 years ago
An electric water heater consumes 2.5 kW for 1.9 h per day.
Alecsey [184]

Answer:

The cost of running the electric water heater for one year is 55.2391 $

Explanation:

The simple rule of 3 helps to quickly solve proportionality problems when you have three known values ​​and one unknown. If two quantities are directly proportional (that is, when multiplying or dividing one of them by a number, the other is multiplied or divided respectively by the same number) the rule of three can be applied as follows:

a ⇒ b

c ⇒ x

So: x=\frac{c*b}{a}

where a, b and c are the known values ​​and x is the value you want to find out.

In this case, you can first apply the following rule of three: if 2.5 kW are consumed in 1.9 hours, in 1 hour how many kW are consumed?

kWh=\frac{1 h*2.5 kW}{1.9 h}

kWh=1.316

So an electric water heater consumes 1.316 kWh in one day. You apply another simple rule of three: if the heater in 1 day consumes 1.316 kWh, in 365 days (1 year) how many kWh are consumed?

kWh=\frac{365 days*1.316 kWh}{1 day}

kWh= 480.34

So an electric water heater consumes 480.34 kWh in a year.

If 1 kWh costs 11.5 cents, 480.34 kWh how many cents does it cost?

cost=\frac{480.34 kWh*11.5 cents}{1 kWh}

cost= 5,523.91 cents

Finally, if 100 cents is equal to 1 dollar, 5,523.91 cents, how many dollars are equal?

cost=\frac{5,5523.91 cents*1 dollar}{100 cents}

cost= 55.2391 $

<u><em> The cost of running the electric water heater for one year is 55.2391 $</em></u>

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Forces holding particles together are strongest in a
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What does the doppler effect indicate about the motion of galaxies?
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