All categories

3 years ago

Select all the answers that apply. Which region makes up the suns interior and surface?

1 answer:

6 0

The solar interior includes the core, radiative zone and convective zone. The photosphere is the visible surface of the Sun.

So the answers should be:

A) Photosphere C) Core D) Radioactive zone and F) Convective zone.

I hope this helps. Sorry if I made any mistakes. :)

You might be interested in

Travels 11,000 feet along a dark desert highway if the car averages 84 mph find the amount of time to cover this distance

laila [671]

The time taken by traveler to cover the distance is,

$t=\frac{d}{v}$

Substitute the known values,

$\begin{gathered} t=\frac{(11000\text{ ft)}}{(84\text{ mph)(}\frac{1.46667\text{ ft/s}}{1\text{ mph}})_{}} \\ \approx89.3\text{ s} \end{gathered}$

Therefore, the time taken by traveler to cover the distance is 89.3 s.

5 0

1 year ago

A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduc

marta [7]

This problem uses the relationships among current I, current density J, and drift speed vd. We are given the total of electrons that pass through the wire in t = 3s and the area A, so we use the following equation to to find vd, from J and the known electron density n, so:

$v_{d} = \frac{J}{n\left | q \right |}$

The current I is any motion of charge from one region to another, so this is given by:

 $I = \frac{\Delta Q}{\Delta t} = \frac{9.4x1018electrons}{3s} = 3189.73(A)$

The magnitude of the current density is:

$J = \frac{I}{A} = \frac{3189.73}{2x10^{-6}} = 1594.86(A/m^{2})$

Being:

$A=2mm^{2} = 2x10^{-6}m^{2}$

Finally, for the drift velocity magnitude vd, we find:

 $v_{d} = \frac{1594.86}{5.8x1028\left |1.60x10^{-19}|\right } = 1.67x10^{18}(m/s)$

Notice: The current I is very high for this wire. The given values of the variables are a little bit odd

6 0

3 years ago

What can cause an increase in density that results in a deep ocean current

mrs_skeptik [129]

The movement of plates

5 0

3 years ago

Read 2 more answers

How much would a 75kg man weigh due to the effect of gravity

Nezavi [6.7K]

Answer: 735 N

Explanation:

Weight $W$ is a measure of the gravitational force acting on an object and is directly proportional to the product of the mass $m$ of the body by the acceleration of gravity $g$ :

$W=m.g$

In the case of our planet Earth, the acceleration due gravity is $g=9.8 m/s^{2}$ . So for a man whose mass is $m=75 kg$ , his weight is:

$W=(75 kg)(9.8 m/s^{2})$

$W=735 N$

4 0

3 years ago

A pendulum has 918 J of potential energy at the highest point of a swing. How much kinetic energy will it have at the bottom of

GREYUIT [131]

The kinetic energy at the bottom of the swing is also 918 J.

Assume the origin of the coordinate system to be at the lowest point of the pendulum's swing. A pendulum, when raised to the highest point has potential energy since it is raised to a height h above the origin. At the highest point, the pendulum's velocity becomes zero, hence it has no kinetic energy. Its energy at the highest point is wholly potential.

When the pendulum swings down from its highest position, it gains velocity. Hence a part of its potential energy begins to convert itself into kinetic energy. If no dissipative forces such as air resistance exist, then, the law of conservation of energy can be applied to the swing.

Under the action of conservative forces, the total mechanical energy of a system remains constant.This means that the sum of the potential and kinetic energies of a body remains constant.

When the pendulum reaches the lowest point of its swing, it is at the origin of the chosen coordinate system. Its vertical displacement from the origin is zero, hence its potential energy with respect to the origin is zero. Therefore the entire potential energy of 918 J should have been converted into kinetic energy, according to the law of conservation of energy.

Thus, the kinetic energy of the pendulum at the lowest point of its swing is equal to the potential energy it had at its highest point, which is equal to 918 J.

8 0

3 years ago