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ki77a [65]
3 years ago
9

Select all the answers that apply. Which region makes up the suns interior and surface?

Physics
1 answer:
lora16 [44]3 years ago
6 0

The solar interior includes the core, radiative zone and convective zone. The photosphere is the visible surface of the Sun.

So the answers should be:

<u>A) Photosphere C) Core D) Radioactive zone </u>and<u> F) Convective zone.</u>

I hope this helps. Sorry if I made any mistakes. :)

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An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an elect
beks73 [17]

Answer:

Speed of the alpha particle is v=1.8180\times 10^3m/sec      

Explanation:

We have given charge on alpha particle q=3.2\times 10^{-19}C

Mass of the alpha particle m=6.68\times 10^{-27}kg

Potential difference V=-3.45\times 10^{-3}volt

We have to find the speed of the alpha particle

From energy conservation we know that

\frac{1}{2}mv^2=qV

\frac{1}{2}\times 6.68\times 10^{-27}\times v^2=3.2\times 10^{-19}\times 3.45\times 10^{-3}

v=1.8180\times 10^3m/sec

4 0
3 years ago
In addition to an all-round white light, what light(s) must power-driven vessels less than 65.6 feet (20 meters) long exhibit wh
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The vessel must also have red and green side lights.

The red light is placed on the port (left) side of the boat while the green light is placed on the starboard (right) side of the vehicle. The white lights are on both the masthead (front) and stern (rear) of the boat, unless the vessel is less than 39.4 feet, in which case the front and rear white light may be combined as only one white light.
7 0
3 years ago
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Two marbles are launched at t = 0 in the experiment illustrated in the figure below. Marble 1 is launched horizontally with a sp
Alex787 [66]

Answer:

Two marbles are launched at t = 0 in the experiment illustrated in the figure below. Marble 1 is launched horizontally with a speed of 4.20 m/s from a height h = 0.950 m. Marble 2 is launched from ground level with a speed of 5.94 m/s at an angle above the horizontal. (a) Where would the marbles collide in the absence of gravity? Give the x and y coordinates of the collision point. (b) Where do the marbles collide given that gravity produces a downward acceleration of g = 9.81 m/s2? Give the x and y coordinates.

Explanation:

i want the answer i don't know

7 0
3 years ago
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A wooden piece is made in different shapes take length (l) = radius (r) = 2m Calculate its volume as a:
In-s [12.5K]

This question deals with the volume of different shapes.

a) volume of the sphere is "33.51 m³".

b) volume of the cylinder is "25.13 m³".

a)

The volume of a sphere is given by the following formula:

Volume = \frac{4}{3}\pi r^3\\\\Volume = \frac{4}{3}\pi (2\ m)^3

<u>Volume = 33.51 m³</u>

<u />

b)

The volume of a cylinder is given by the following formula:

Volume = \pi r^2l\\\\Volume =\pi (2\ m)^2(2\ m)

<u>Volume = 25.13 m³</u>

<u />

Learn more about <em>volume </em>here:

brainly.com/question/16686115?referrer=searchResults

The attached picture shows the formulae of the <em>volume</em> of different shapes.

7 0
3 years ago
A potential difference of 3.00 nV is set up across a 2.00 cm length of copper wire that has a radius of 2.00 mm. How much charge
Anvisha [2.4K]

The number of charge drifts are 3.35 X 10⁻⁷C

<u>Explanation:</u>

Given:

Potential difference, V = 3 nV = 3 X 10⁻⁹m

Length of wire, L = 2 cm = 0.02 m

Radius of the wire, r = 2 mm = 2 X 10⁻³m

Cross section, 3 ms

charge drifts, q = ?

We know,

the charge drifts through the copper wire is given by

q = iΔt

where Δt = 3 X 10⁻³s

and i = \frac{V}{R}

where R is the resistance

R = \frac{pL}{r^{2} \pi }

ρ is the resistivity of the copper wire = 1.69 X 10⁻⁸Ωm

So, i = \frac{\pi(r)^{2}V  }{pL}

q = \frac{\pi(r^{2} )Vt }{pL}

Substituting the values,

q = 3.14 X (0.02)² X 3 X 10⁻⁹ X 3 X 10⁻³ / 1.69 X 10⁻⁸ X 0.02

q = 3.35 X 10⁻⁷C

Therefore, the number of charge drifts are 3.35 X 10⁻⁷C

3 0
3 years ago
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