Answer:
True
Explanation:
Step 1: Find molecular formula of sucrose
C₁₂H₂₂O₁₁
Step 2: Convert moles of oxygen present to grams
1 mol O = 16 g O
11 mol O = 176 g O
Step 3: Find molar mass of sucrose
C - 12.01 g/mol
H - 1.01 g/mol
O - 16.00 g/mol
12.01(12) + 22(1.01) + 11(16.00) = 342.34 g/mol C₁₂H₂₂O₁₁
Step 4: Set up dimensional analysis
Step 5: Multiply/Divide and cancel out units
Grams of C₁₂H₂₂O₁₁ and grams of C₁₂H₂₂O₁₁ cancel out.
We are left with grams Oxygen
176/342.34 = 0.514109 grams Oxygen
Answer:
By visiting other households with cats.
Explanation:
This will give Brian a variety of other houses and determine if it is truly cats or just alleries from other items. This is the most direct way to get Brian the answer he is looking for.
The mass number of an atom : 26
<h3>Further explanation</h3>
Given
12 protons, 14 neutrons, and 12 electrons
Required
The mass number
Solution
Inside the atom there are 3 sub-particles, namely protons, neutrons and electrons. Protons and electrons are present in the atomic nucleus while electrons move around the atomic nucleus through energy levels in the atomic shell
Atomic number = number of protons = number of electrons
Mass number = number of protons + number of neutrons
Input the value :
Mass number = 12 + 14
Mass number = 26
Answer:
The atomic weight of hypothetical element will be 63.568 amu.
Explanation:
Given data:
First isotope mass = 62.2 amu
Percentage abundance of first isotope = 24%
Mass of second isotope = 64 amu
Percentage abundance of second isotope = 100- 24 = 76%
Solution:
The atomic weight of hypothetical element will be the average atomic mass of its isotopes.
Average atomic mass = [mass of isotope× its abundance] + [mass of isotope× its abundance] +...[ ] / 100
Now we will put the values in formula.
Average atomic mass = [24 ×62.2] + [76× 64] / 100
Average atomic mass = 1492.8 + 4864 / 100
Average atomic mass = 6356.8/100
Average atomic mass = 63.568 amu
When warm air rises, cooler air will move in to replace it, so wind often moves from colder areas to warmer areas. The greater the difference between the high and low pressure or the shorter the distance between the high and low pressure areas, the faster the wind will blow
So the correct answer will be:
When a high and a low pressure air mass are far apart, air moves slowly from high to low pressure
