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3 years ago

Brian's aunt has cats. When Brian recently visited her, he started sneezing badly and believes that it was because

Chemistry

1 answer:

kifflom [539]3 years ago

4 0

Answer:

By visiting other households with cats.

Explanation:

This will give Brian a variety of other houses and determine if it is truly cats or just alleries from other items. This is the most direct way to get Brian the answer he is looking for.

You might be interested in

An atom of chromium has 24 protons, 28 neutrons, and 24 electrons. A chromium atom has_____Subatomic particles in the necleus

navik [9.2K]

3 subatomic particles in the nucleus
which is proton(24),neutron (28) and electrons(24)

5 0

3 years ago

Write the net ionic equation for the reaction between hydrocyanic acid and potassium hydroxide. Do not include states such as (a

eimsori [14]

Answer:

The net ionic equation is as follows:

HCN(aq) + OH-(aq) ----> H20(l) + CN-(aq)

Explanation:

The reaction between Hydrocyanic acid, HCN, and sodium hydroxide is a neutralization reaction between a weak acid and a strong base.

Hydrocyanic acid being a weak acid ionizes only slightly, while sodium hydroxide being a strong base ionizes completely. The equation for the reaction is given below:

A. HCN(aq) + NaOH-(aq) ----> NaCN(aq) + H2O(l)

Since Hydrocyanic acid is written in the aqueous form as it ionizes only slightly and the ionic equation is given below:

HCN(aq) + Na+(aq)+OH-(aq) ----> Na+(aq)+CN-(aq) + H2O(l)

Na+ being a spectator ion is removed from the net ionic equation given below:

HCN(aq) + OH-(aq) ----> H20(l) + CN-(aq)

4 0

3 years ago

As student used a pen to draw a line across a piece of chromatography paper. he then placed a sample of dye on the drawn line fo

AleksAgata [21]

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wpazsebu

3 0

2 years ago

Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate

uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: $m_{(AcO)_2Cu} = 0.972 g$

Volume of the sodium chromate solution: $V_{Na_2CrO_4} = 150.0 mL$

Molarity of the sodium chromate solution: $c_{Na_2CrO_4} = 0.0400 M$

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

$(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)$

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

$n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol$

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

$n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol$

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

$Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)$