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alexandr1967 [171]

3 years ago

14

Which of the following is true about the relationship between changes in air pressure and wind speeds plz right answers..... hel

p!!!

2 answers:

GalinKa [24]3 years ago

7 0

When a high and a low pressure air mass are far apart, air moves slowly from high to low pressure

I hope helpded ^-^

svp [43]3 years ago

5 0

When warm air rises, cooler air will move in to replace it, so wind often moves from colder areas to warmer areas. The greater the difference between the high and low pressure or the shorter the distance between the high and low pressure areas, the faster the wind will blow
So the correct answer will be:
When a high and a low pressure air mass are far apart, air moves slowly from high to low pressure

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Around four hundred million years after the formation of Earth, the planet's atmosphere would have been almost entirely _____.

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the answer is option d

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3 years ago

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A solution of phosphoric acid was made by dissolving 10.0 g of H3PO4 in 100.0 mL of water. The resulting volume was 113 mL. Calc

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Explanation:

Mass of solute = 10.0 g

mass of solvent(water) = m

Volume of solvent( water) = v = 100.0 mL

Density of water= d = $1 g/cm^3=1 g/mL$

$1 mL= 1 cm^3$

$m=d\times v=1.0 g/mL\times 100.0 = 100.0 g$

Mass of solution(M) = Mass of solute + mass of solvent

M = 10.0 g + 100.0 g = 110.0 g

Volume of the solution = V = 113 mL

Density of the solution = D

$D=\frac{M}{V}=\frac{110.0 g}{113 mL}=0.9734 g/mL$

The density of the solution is 0.9734 g/ml.

Moles of phosphoric acid = $n_1=\frac{10.0 g}{98 g/mol}=0.1020 mol$

Moles of water = $n_2=\frac{100.0 g}{18g/mol}=5.556 mol$

Mole fraction of phosphoric acid = $\chi_1$

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1020 mol}{0.1020 mol+5.556 mol}$

$\chi_1=0.01803$

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$\chi_2=\frac{n_2}{n_1+n_2}=\frac{5.556 mol}{0.1020 mol+5.556 mol}$

$\chi_2=0.9820$

$[Molarity]=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}$

Moles of phosphoric acid = 0.1020 mol

Volume of the solution = V = 113 mL = 0.113 L ( 1 mL = 0.001 L)

Molarity of the solution :

$=\frac{0.1020 mol}{0.113 L}=0.903 M$

$[Molality]=\frac{\text{Moles of solute}}{\text{Mass of solvent(kg)}}$

Moles of phosphoric acid = 0.1020 mol

Mass of solvent(water) = m =100.0 g = 0.100 kg ( 1 g = 0.001 kg)

Molality of the solution :

$=\frac{0.1020 mol}{0.100 kg}=1.02 mol/kg$

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3 years ago

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gayaneshka [121]

They share the same number or protons

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3 years ago

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MAXImum [283]

Answer:

a

Explanation:

7 0

3 years ago

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How many moles of oxygen will occupy a volume of 2.50 liters?

loris [4]

Data:
n (number of mols) = ?
V (volume) = 2.50 Liters
If:
1 L → 1000 g
2.50 L → y

y = 1000*2.50 = 2500 g

Therefore:
m (mass) = 2500 g

Now:
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Formula:
$n = \frac{m}{MM}$

Solving:
$n = \frac{m}{MM}$
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$\boxed{\boxed{n = 156.25\:mols}}\end{array}}\qquad\quad\checkmark$

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3 years ago