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Rudiy27
2 years ago
15

Task Three :Write a C++ program to read temperature

Engineering
1 answer:
leva [86]2 years ago
3 0

Answer:

Write a program in C++ to convert temperature in Fahrenheit to Celsius.

Sample Solution:

C++ Code :

#include <iostream>

using namespace std;

int main()

{

   float frh, cel;

cout << "\n\n Convert temperature in Fahrenheit to Celsius :\n";

cout << "---------------------------------------------------\n";

   cout << " Input the temperature in Fahrenheit : ";

   cin >> frh;

   cel = ((frh * 5.0)-(5.0 * 32))/9;

   cout << " The temperature in Fahrenheit : " << frh << endl;

   cout << " The temperature in Celsius : " << cel << endl;

cout << endl;

   return 0;

Explanation:

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Explanation:

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Hope that helps!

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3 years ago
ANSWER QUICK<br>Why did Winston Churchill take over for Neville Chamberlain shortly after ww2? ​
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4 years ago
A budding electronics hobbyist wants to make a simple 1.0-nF capacitor for tuning her crystal radio, using two sheets of aluminu
bazaltina [42]

Answer:

a. 8 sheets of paper is needed between her plates to get the proper capacitance

b. Area of Aluminum Foil needed = 0.45m²

c. To keep a 1.0-nF, a larger area of Teflon is required.

Explanation:

a.

First, we need to calculate the distance between two plates.

This is given by

d = Kε0A/C

Where

K = 3

ε0 = Physical Constant = 8.854 * 10^-12 C²/Nm²

A = Area = 22 * 28 = 616cm² = 0.0616m²

C = 1.0-nF = 1 * 10^-12F

So, d = (3 * 8.854 * 10^-12 C²/Nm² * 0.0616) / (1 * 10^-12F)

d = 1.64 * 10^-3m

d = 1.64mm

Now, that the distance has been solved.

The Number of Sheets, N is given by

N = d/d,sheet where d, sheet =the sheet thickness = 0.2mm

N = 1.64/0.2

N = 8.2

N = 8 sheets --- Approximated

b.

Here, she's changed the diameter of the sheets to 12mm

Well make use of the formula in (a) above

Using d = Kε0A/C

Where

d = 12 * 10^-3m

Other constraints remain unchanged

Make A the subject of formula

A = dC/Kε0

A = (12 * 10^-3m * 1 * 10^-12F)/(3 * 8.854 * 10^-12 C²/Nm²)

A= 0.45m²

c. From (b) above

A ∝ 1/K

As the dielectric constant increase, the area decreases

The dielectric constant of a Teflon is 2.1

This means that if she used a Teflon instead, the area will be larger.

So, to keep a 1.0-nF, a larger area of Teflon is required.

7 0
3 years ago
If you measure 0.7 V across a diode, the diode is probably made of
tatuchka [14]

Answer:

Made of Silicon.

Explanation:

A diode is a semiconductor device use in mostly electronic appliances. It is two terminals device consisting of a P-N junction formed either in Germanium or silicon crystal.

Diode can be forward biased or reverse biased.

When a diode is forward biased and the applied voltage is increased from zero, hardly any current flows through the device in the beginning.

It is so because the external voltage is being opposed by the internal barrier voltage whose value is 0.7v for silicon and 0.3v for germanium.

If you measure 0.7 V across a diode, the diode is probably therefore made of Silicon.

6 0
3 years ago
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